All categories

3 years ago

Please help helppp :((((

Mathematics

1 answer:

ella [17]3 years ago

4 0

Answer:

m∠Q = 61°

m∠S = 61°

m∠R = 58°

Step-by-step explanation:

Since we have an isosceles triangle, we know that ∠Q and ∠S are congruent.

Step 1: Definition of isosceles triangle

2x + 41 = 3x + 31

41 = x + 31

x = 10

Step 2: Find m∠Q

m∠Q = 2(10) + 41

m∠Q = 20 + 41

m∠Q = 61°

Step 3: Find m∠S

Since m∠Q = m∠S,

m∠S = 61°

Step 4: Find m∠R (Definition of a triangle)

Sum of angles in a triangle adds up to 180°

m∠R = 180 - (61 + 61)

m∠R = 180 - 122

m∠R = 58°

You might be interested in

Unattached earlobes are a dominant trait in humans. finn and maggie both have unattached earlobes but their daughter, celia, doe

11111nata11111 [884]

The answer is 1/4.

The genes when combined must be Heterozygous, meaning they have one dominant and one recessive, Celia must have gotten the 1/4 recessive, and it won't change the way genetics are just because you've already had offspring, the percentage stays the same.

6 0

3 years ago

More than one unknown in a word problem can be represented in terms of the same variable assigned to first unknown

DIA [1.3K]

What exactly do you want to know? make it clear??

7 0

3 years ago

Find the fifth roots of 243(cos 260° + i sin 260°).

Dmitry [639]

Answer:

z1=3 cos (52 + i sin 52)

z2 =3 cos (124 + i sin 124)

z3 = 3 cos (196 + i sin 196)

z4 =3 cos (268 + i sin 268)

z5= 3 cos (340 + i sin 340)

Step-by-step explanation:

To find the fifth roots of 243 (cos 260° + i sin 260°).

z ^ 1/5 = r^1/5 ( cis ( theta + 360 *k)/5) where k=0,1,2,3,4

So the first root of 243 (cos 260° + i sin 260°)

is z1 = 243^1/5 ( cis ( 260 + 360 *0)/5)

3 cis ( 260/5)

= 3 cis (52)

= 3 cos (52 + i sin 52)

The second root of 243 (cos 260° + i sin 260°)

is z2 = 243^1/5 ( cis ( 260 + 360 *1)/5)

3 cis ( 620/5)

= 3 cis (124)

= 3 cos (124 + i sin 124)

The third root of 243 (cos 260° + i sin 260°)

is z3 = 243^1/5 ( cis ( 260 + 360 *2)/5)

3 cis ( 980/5)

= 3 cis (196)

= 3 cos (196 + i sin 196)

The fourth root of 243 (cos 260° + i sin 260°)

is z4 = 243^1/5 ( cis ( 260 + 360 *3)/5)

3 cis ( 1340/5)

= 3 cis (268)

= 3 cos (268 + i sin 268)

The fifth root of 243 (cos 260° + i sin 260°)

is z5 = 243^1/5 ( cis ( 260 + 360 *4)/5)

3 cis ( 1700/5)

= 3 cis (340)

= 3 cos (340 + i sin 340)

6 0

3 years ago

1. Graph the set of integers (-2, -5, 1} on a number line.

ivanzaharov [21]

Answer: Its below

Step-by-step explanation:

4 0

3 years ago

In △JKL, solve for x. a) 17.32 b) 38.16 c) 66.73 d) 74.89

natita [175]

Answer:

c) 66.73

Step-by-step explanation:

We have been given a right triangle. We are asked to find the value of x for our given triangle.

We can see that x is adjacent side for angle 27 degrees and side Kl is opposite side.

We know that tangent relates opposite side of right triangle to its adjacent side.

$\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}$

Upon substituting our given values, we will get:

$\text{tan}(27^{\circ})=\frac{34}{x}$

$x=\frac{34}{\text{tan}(27^{\circ})}$

$x=\frac{34}{0.509525449494}$

$x=66.728757\approx 66.73$

Therefore, the value of x is 66.73 for our given triangle and option 'c' is the correct choice.

8 0

3 years ago