Answer:
False
Step-by-step explanation:
0.15/10 equals 0.015
Given:
n = 20, sample size
xbar = 17.5, sample mean
s = 3.8, sample standard deiation
99% confidence interval
The degrees of freedom is
df = n-1 = 19
We do not know the population standard deviation, so we should determine t* that corresponds to df = 19.
From a one-tailed distribution, 99% CI means using a p-value of 0.005.
Obtain
t* = 2.8609.
The 99% confidence interval is
xbar +/- t*(s/√n)
t*(s/√n) = 2.8609*(3.8/√20) = 2.4309
The 99% confidence interval is
(17.5 - 2.4309, 17.5 + 2.4309) = (15.069, 19.931)
Answer: The 99% confidence interval is (15.07, 19.93)
Answer:
let p be the population proportion of parents who had children in grades k-12 were satisfied with the quality of education the students receive.
Step-by-step explanation:
400+30+7. +0+4
3,000,000+500+40+3,000+2+1
In 5xy it would be 5x×1y and then 2y if they variable doesn't have a number infront of it it is assumed to be a One.
