0.78 strikeouts per minute
The graphs that are density curves for a continuous random variable are: Graph A, C, D and E.
<h3>How to determine the density curves?</h3>
In Geometry, the area of the density curves for a continuous random variable must always be equal to one (1). Thus, we would test this rule in each of the curves:
Area A = (1 × 5 + 1 × 3 + 1 × 2) × 0.1
Area A = 10 × 0.1
Area A = 1 sq. units (True).
For curve B, we have:
Area B = (3 × 3) × 0.1
Area B = 9 × 0.1
Area B = 0.9 sq. units (False).
For curve C, we have:
Area C = (3 × 4 - 2 × 1) × 0.1
Area C = 10 × 0.1
Area C = 1 sq. units (False).
For curve D, we have:
Area D = (1 × 4 + 1 × 3 + 1 × 2 + 1 × 1) × 0.1
Area D = 10 × 0.1
Area D = 1 sq. units (True).
For curve E, we have:
Area E = (1/2 × 4 × 5) × 0.1
Area E = 10 × 0.1
Area E = 1 sq. units (True).
Read more on density curves here: brainly.com/question/26559908
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Answer: -1/2, -0.22, 0, 12%, 0.56
Step-by-step explanation:
-1/2 is equal to -0.50, making it the number with the least value.
-0.22 is closer to 0 than -0.50, meaning it is greater then -0.50 and less than 0.
0 is between the negative and positive numbers, giving it the spot that it has.
12% is equivalent to 0.12, meaning it is more than 0, and less than 0.56, which is the greatest number.
0.56 has more value than any other number in the problem, meaning it goes last in the order.
Answer:
(D)5
Step-by-step explanation:
Given the point J(-3,1) and K(8,11).
The line segment that divides the segment from J to K in any given ratio can be determined using the formula.
In the given case:
, m:n=2:3
Since we are to determine the y-coordinate of the point that divides JK into a ratio of 2:3, we have:
The y-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:3 is 5.
The correct option is D.
