Your answer should be C. 3x^3√2
Step-by-step explanation:
Putting both functions into a graphing calculator, we can easily find the domain and range. (attatched)
By looking at the graph, we can tell that f(x) is a quadratic function because of the symmetry. We can also tell that it never goes below 4. Knowing this, we can determine the domain and range.
Domain: {x | all real numbers}
Range: {y | y > 4}
By looking at the graph, we can tell that g(x) is an exponential function because it has a curve, and never goes below the x. Knowing this, we can determine the domain and range.
Domain: {x | all real numbers}
Range: {y | y > 0}
The property where you multiply ig
The subtraction property of equality: if we subtract one side of the equation then we also must subtract from the other side of the equation.
The division property of equality: if we divide one side of the equation by a number then we also must divide the other side by the same number.
For this equation:
3 x + 5 = 26
3 x + 5 - 5 = 26 - 5 ( the Subtraction Property of Equality )
3 x = 21
3 x : 3 = 21 : 3 ( the Division Property of Equality )
x = 7
Answer: C ) The standard method for solving an equation like 3 x + 5 = 26 is to use the Subtraction Property of Equality and then the Division Property of Equality.
Answer:
A. 183 meters
Step-by-step explanation:
Building A and building B are 500 meters apart. There is no road between them, so to drive from building A to building B, it is necessary to first drive to building C and then to building B. About how much farther is it to drive than to walk directly from building A to building B? Round to the nearest whole number. A) 183 meters B) 250 meters C) 366 meters D) 683 meters
Find distance BC
Cos (60°)=BC / AB (Adjacent divided by the hypotenuse)
Cos (60°)=1/2
BC=a
AB=500
Cos (60°)=BC / AB
1/2=a/500
1/2 * 500=a
250=a
a=250m
Find distance AC
Sin(60°)=AC/AB (opposite side divided by hypotenuse)
Sin(60°)=√3/2
AC=b
AB=500
Sin(60°)=AC/AB
√3/2=b/500
√3/2 * 500=b
250√3=b
b=433m
Distance AC and BC=AC+BC
433m+250m=683m
Subtract the distance AB from AC+BC
= 683m - 500m
=183m
Answer is A. 183 meters