First, add. 11/10 + 23/10 = 34/10
You can then simplify by finding the greatest common factor (2)
34/2, 10/2 = 17/5, or 3 and 2/5
Andrei is 3 and 2/5 meters tall
In what I know of this problem and what you told me I think there is a 1/2 chance!
think about it, if the life span is 15 years old with standard deviation of 3 then that means we can have bats from 12~18 years old and the mean of the 50 numbers can be anything between that depending on the results we got. Then half of values in interval 12~18 is over 15 which gives it a 1/2 probability!
Answer:
a) -1.25
b) 0.2112
c) -1.96
Step-by-step explanation:
Data provided in the question:
Sample size, n = 400
H0 : p = 20
= 175
Now,
a) The test statistic is given as:
Z = 
on substituting the respective values, we get
Z = 
= -1.25
b) The p-value = 2 × P(Z <-1.25)
Now from the standard normal table
P(Z <-1.25) = 10.56% = 0.1056
Thus,
p-value = 2 × 1056 = 0.2112
c) for a = 0.05,
the critical value is
i.e 
Now from standard normal table
= -1.96
The answer is A. bc of the point