<span>Rx h= ax-k
</span><span>Rxh−ax=−k
</span><span><span>x(rh−a)=−k ( here i took the common one out ..)
x = - k/ rh-a
Hope it helps !!!
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The correct answer is: [A]: " t = 15n " .
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You can search in google if you want for the "inscribed quadrilateral conjecture"
and if you want... I can give you a quick proof of it
hmmm in short, if you inscribe a quadrilateral polygon in a circle
it will have 4 angles
each pair of opposite angles, are "supplementary angles", or they add up to 180°
so.. that said in yours, R+P = 180 and Q+O = 180 as well
you only need Q
so

solve for "x"
how big is Q? well, 2x + 4 :)
Answer:

Step-by-step explanation:
First, find the area of the bigger shape. Then, separately, find the smaller shape's area. Subtract the smaller one by the big boi, and you'll get the area of the shaded area. You can count the little squares too.
12*8=96
4*6=24
96-24=72
No.
9514 1404 393
Answer:
y = 6^x -3
Step-by-step explanation:
The graph is that of an exponential function that has been translated downward. We notice the horizontal asymptote is -3, and a couple of points on the graph are (0, -2) and (1, 3).
The shifted parent function will look like ...
y = a·b^x +c
where c is the horizontal asymptote. Using the two points we found, we have ...
-2 = a·b^0 -3 . . . . . using (x, y) = (0, -2)
1 = a . . . . . . . . . . add 3 and simplify
Then using (x, y) = (1, 3), we have ...
3 = b^1 -3
6 = b . . . . . . . . . add 3 and simplify
So, the equation is ...
y = 6^x -3