Circumference = 2Pi * r
28.3cm = 2pi * r ( Isolate r )
28.3cm / 2pi = r
R = 4.504
To verify work we can plug 4.504 back into the equations.
Circumference = 2pi*4.504 ~ 28.299 Which is true !
The cage will drop 18.84m for each single rotation of the drum.
It is given that the diameter of the mine winch, d= 6 m.
We can calculate that how far the cage will drop for each single rotation of the drum by using the formula of the circumference.
Circumference, c = 2πr
where,
r = d/2 (radius of the mine winch)
r = 6/2
⇒ r = 3m
Circumference, c = 2πr
⇒ c = 2π×(3)
⇒ c = 6π
⇒ c = 18.84m
Hence, the cage will drop 18.84m for each single rotation of the drum.
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Answer:
AC and AE
Step-by-step explanation:
Those are the only secants in the image shown.
Answer:
answer 1
Step-by-step explanation:
Since there's only 1 value in the 90-99 groups it is either 1 or 3.
Furthermore, there are only 2 values starting with 10.
This only fits with answer 1
Hello from MrBillDoesMath!
Answer: 1/2
Discussion:
Note that:
16 /2 = 8 (the next term in the sequence)
8 /2 = 4 (the next term in the sequence)
4 /2 = 2 (the next term in the sequence)
We are repeatedly multiplying by 1/2
Thank you,
MrB
