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USPshnik [31]
2 years ago
14

If the sides of a triangle are in the ratio 3:4:5, prove that it isright-angled triangle​

Mathematics
2 answers:
Natali5045456 [20]2 years ago
8 0

Answer:

yes it's a right angle triangle

Step-by-step explanation:

Given the sides are in the ratio 3:4:5.

Let ABC be the given triangle.

Let the sides be 3x,4x and hypotenuse be 5x.

According to Pythagoras theorem,

AC

2

=BC

2

+AB

2

BC

2

+AB

2

=(3x)

2

+(4x)

2

=9x

2

+16x

2

=25x

2

AC

2

=(5x)

2

=25x

2

AC

2

=BC

2

+AB

2

Hence ABC is a right angled triangle

lyudmila [28]2 years ago
6 0

Answer:

hope this helps

Step-by-step explanation:

Let a , b , c are three sides of a triangle

a : b : c = 3 : 4 : 5

a = 3x ,

b = 4x ,

c = 5x

a² = 9x²

b² = 16x²,

c² = 25x².

c² = a² + b²

by the pythagorean theorem,

a , b , c forms a right angled Triangle.

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7 0
3 years ago
The population of a town is 6500 and is increasing at a rate of 4% each year. Create a function for this scenario. At this rate,
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Answer:

P_4 = 7604.08

Step-by-step explanation:

If the population increases at a rate of 4% per annum, then:

In year 1:

P_1 = P_0 + 0.04P_0

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In year 2

P_2 = P_1 + 0.04P_1

It can also be written as:

P_2 = P_0 + 0.04P_0 + 0.04 (P_0 + 0.04P_0)

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P_2 = (1 + 0.04) (P_0) + 0.04P_0 (1 + 0.04)

Taking out common factor (1 + 0.04)

P_2 = (1 + 0.04) (P_0 + 0.04P_0)

Taking out again common factor P_0

P_2 = (1 + 0.04) (1 + 0.04) P_0

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So

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