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GREYUIT [131]
3 years ago
14

I am so confused can someone help me asap??

Mathematics
1 answer:
erica [24]3 years ago
5 0
Can you take a more clear picture?? I can’t read it well. Looks like the awnser may be congruent. Yes
You might be interested in
A room is 4 m wide and 1.5 times as long as it is wide. Its height is 1/2 the length. Find the mass of the air in the room if 1m
Elena L [17]

Answer: 93.6

Step-by-step explanation:

Width: 4

Length: 4*1.5=6

Height: 6/2=3

4*6*3=72

72*1 3/10= 93.6

8 0
3 years ago
Read 2 more answers
Solve for w, where w is a real number.
Ber [7]

Answer:

w= 9

Step-by-step explanation:

\sqrt{ - 4w + 61}  = w - 4

Square both sides:

-4w +61= (w -4)²

\boxed{(a - b)^{2}  = a^2 -2ab + b^2 }

Expand:

-4w +61= w² -2(w)(4) +4²

-4w +61= w² -8w +16

Simplify:

w² -8w +16 +4w -61= 0

w² -4w -45= 0

Factorize:

(w -9)(w +5)= 0

w -9= 0 or w +5= 0

w= 9 or w= -5 (reject)

Note:

-5 is rejected since we are only taking the positive value of the square root here. If the negative square root is taken into consideration, then w= -5 would give us -9 on both sides of the equation.

<u>Why </u><u>do </u><u>we </u><u>use </u><u>negative </u><u>square </u><u>root?</u>

When solving an equation such as x²= 4,

we have to consider than squaring any number removes the negative sign i.e., the result of a squared number is always positive.

In the case of x²= 4, x can be 2 or -2. Thus, whenever we introduce a square root, a '±' must be used.

However, back to our question, we did not introduce the square root so we should not consider the negative square root value.

6 0
2 years ago
Read 2 more answers
When you translate, (x, y+6) will move
Darya [45]

Answer:

(x, y+6) will vertically move 6 units up.

Step-by-step explanation:

If we move vertically 6 units up, 6 is added to the y-coordinate.

so

(x, y+6) will vertically move 6 units up.

For example, let suppose the point P(-2, 3). When we apply a translation of (x, y+6) to the point P(-2, 3), the coordinates of point P after the translation will be:

(x, y)              →                 (x, y+6)

P(-2, 3)          →                 P(-2, 9)             ∵ P(-2, 3+6)

Therefore, (x, y+6) will vertically move 6 units up.

4 0
3 years ago
Orthogonalizing vectors. Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, a
jeka57 [31]

Answer:

\\ \gamma= \frac{a\cdot b}{b\cdot b}

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if b \neq 0. Recall that given two vectors a,b  a⊥ b if and only if a\cdot b =0 where \cdot is the dot product defined in \mathbb{R}^n. Suposse that b\neq 0. We want to find γ such that (a-\gamma b)\cdot b=0. Given that the dot product can be distributed and that it is linear, the following equation is obtained

(a-\gamma b)\cdot b = 0 = a\cdot b - (\gamma b)\cdot b= a\cdot b - \gamma b\cdot b

Recall that a\cdot b, b\cdot b are both real numbers, so by solving the value of γ, we get that

\gamma= \frac{a\cdot b}{b\cdot b}

By construction, this γ is unique if b\neq 0, since if there was a \gamma_2 such that (a-\gamma_2b)\cdot b = 0, then

\gamma_2 = \frac{a\cdot b}{b\cdot b}= \gamma

6 0
3 years ago
Determine whether the sequence is arithmetic, geometric, both, or neither. 1, 4, 9, 16, 25, . . .
klemol [59]

Answer:

neither

Step-by-step explanation:

First differences are 3, 5, 7, 9, and the differences of these (2nd differences) are constant at 2. The degree of the polynomial function describing the sequence is equal to the number of the differences that are constant. Here, that is 2nd differences, so the sequences is described by a 2nd-degree (quadratic) polynomial.

It is not linear (arithmetic) or exponential (first differences have a common ratio).

6 0
3 years ago
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