The probability of a hand of 13 cards contains all 4 of one of the denominations, say Aces, is given by:
$\frac{4C4\times48C9}{52C13}=0.00264106$
The same probability applies to getting all 4 of each of the other denominations.
Therefore the required probability is:
$0.00264106\times13=0.0343$
The answer is 0.0343.

5 0

4 years ago

You are volunteering to help with the soccer team fundraiser for Valentine's Day. Your team promised to deliver one 16 ounce bag

icang [17]

The student, who suggests that if we do half and half of each bag, we will be giving them at least 60%,<u> is correct</u>.

<h3>What is the implication of the phrase "at least"?</h3>

The phrase "at least" means the minimum that is true or possible.

Mathematically, by "at least," we mean 'equal to or greater than.'

<h3>Data and Calculations:</h3>

Since each bag of nuts contain 16 ounces,

The 1st bag contains x/2 ounces (50%) of plain nuts and x/2 ounces (50%) of chocolate-covered nuts.

The 2nd bag contains x/5 ounces (20%)of plain nuts and 4x/5 ounces (80%) of chocolate-covered nuts.

If half of the 1st bag is mixed with half of the 2nd bag, each bag will contain only 65% (that is, 25% (50%/2) from the 1st bag and 40% (80%/2) from the 2nd bag).

Thus, the student, who suggests that if we do half and half of each bag, we will be giving them at least 60%, <u>is correct</u> since they will not be given less than 60% of chocolate-covered nuts inside.

Learn more about proportions at brainly.com/question/870035

#SPJ1

7 0

2 years ago