Question

Can someone answer these two questions I submitted a photo of them it’s worth 50 points

Answer 1

Answer:

Step-by-step explanation:

1). Let the equation of the line is,

  y = mx + b

  Here, m = slope of the line

  b = y-intercept

  Slope of a line passing through two points,

  m = $\frac{y_2-y_1}{x_2-x_1}$

  We take two points from the table given (-3, -19) and (0, -1)

  m = $\frac{-19+1}{-3-0}$

  m = 6

  y - intercept 'b' = -1 [For x = 0]

  Therefore, equation of the line will be,

  y = 6x - 1

2). Equation of a line passing through a point (x', y') is,

   y - y' = m(x - x')

   Slope of the line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is,

   m = $\frac{y_2-y_1}{x_2-x_1}$

   We take two points from the given table as (2, 12) and (3, 18).

   Slope of the line passing through these points will be

   m = $\frac{18-12}{3-2}$ = 6

   Equation of the line passing through (2, 12) will be,

   y - 12 = 6(x - 2)

   y = 6x - 12 + 12

   y = 6x

By using a graphing tool we can graph these lines representing the tables.