16x^4-81y^4 difference of perfect squares...
(4x^2-9y^2)(4x^2+9y^2) that's one of the equivalents...
(2x+3y)(2x-3y)(4x^2+9y^2) that's another one of them...
x ≈ 59°
Work is on piece of paper, yet I don't have a phone. I'm certain that is the answer.
Answer:
y = 1/3
Step-by-step explanation:
<u>Step 1: Factor</u>
9y^2 - 6y + 1 = 0
(3y - 1)(3y - 1) = 0
(3y - 1)^2 = 0
<u>Step 2: Solve for y</u>
3y - 1 + 1 = 0 + 1
3y / 3 = 1 / 3
y = 1/3
Answer: y = 1/3
