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Rus_ich [418]
2 years ago
9

A side of 6 feet, and a 120° angle A. One B. None. C. Many

Mathematics
1 answer:
pshichka [43]2 years ago
5 0

Answer:

C. Many ang sagot............

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What is r i 4.5+10r=-6.5 with work pls
Evgen [1.6K]

Answer:

-11/10 or -1.1

Step-by-step explanation:

To start, let's get rid of those pesky decimals by multiplying everything by 2. Then we get 9 + 20r = -13. Now, let's isolate the r by subtracting 9 from both sides to get 20r = -22. Finally, we need to divide everything by 20 to get r = -11/10 or -1.1.

8 0
3 years ago
Use a graph in a (-2π, 2π, π/2) by (-3, 3, 1) viewing rectangle to complete the identity.
yaroslaw [1]

First, notice that:

2\tan (\frac{x}{2})=2\cdot(\pm\sqrt[]{\frac{1-cosx}{1+\cos x})}

And in the denominator we have:

1+\tan ^2(\frac{x}{2})=1+\frac{1-\cos x}{1+\cos x}=\frac{1+cosx+1-\cos x}{1+cosx}=\frac{2}{1+\cos x}

then, we have on the original expression:

\begin{gathered} \frac{2\tan(\frac{x}{2})}{1+\tan^2(\frac{x}{2})}=\frac{2\cdot\pm\sqrt[]{\frac{1-\cos x}{1+cosx}}}{\frac{2}{1+\cos x}}=\frac{2\cdot(\pm\sqrt[]{1-cosx})\cdot(1+\cos x)}{2\cdot(\sqrt[]{1+cosx})} \\ =(\sqrt[]{1-\cos x})\cdot(\sqrt[]{1+\cos x})=\sqrt[]{(1-\cos x)(1+\cos x)} \\ =\sqrt[]{1-\cos^2x}=\sqrt[]{\sin^2x}=\sin x \end{gathered}

therefore, the identity equals to sinx

8 0
1 year ago
Hello people I can use some help
serious [3.7K]

Answer:

The inverse operation is division

5 0
3 years ago
The proof that ΔQPT ≅ ΔQRT is shown. Given: SP ≅ SR Prove: ΔQPT ≅ ΔQRT
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The answer is D. 4x7+5=33 8x7+5=61. Hope it helps
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3 years ago
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