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3 years ago

P(getting exactly 7 correct) = 0.0031

Mathematics

2 answers:

GarryVolchara [31]3 years ago

7 0

Answer:

Sample Response: The probability gets smaller and approaches 0 because 9 or 10 successes in 10 trials is unlikely.

PSYCHO15rus [73]3 years ago

3 0

Answer:

The probability gets smaller and approaches 0 because 9 or 10 successes in 10 trials is unlikely.

Step-by-step explanation:

I just took the test.

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find all possible value of the given variable

mamaluj [8]

$1.\\ \\ h^2+5h=0 \\ \\h(x+5)=0\\ \\x=0 \ \ \ or \ \ \ x+5 =0\ \ |-5\\ \\x+5-5=0-5\\ \\x=0 \ \ \ or \ \ \ x=-5$

$2.\\ \\ z^2-z=0\\ \\z(x-1)=0\\ \\z=0 \ \ \ or \ \ \ z-1 =0 \ \ | +1\\ \\z-1+1 =0 +1 \\ \\x=0 \ \ \ or \ \ \ z=1$

$3.\\ \\m^2+13m+40=0 \\ \\a=1 ,\ b=13, \ c=40 \\ \\\Delta =b^2-4ac =13^2-4\cdot 1\cdot 40=169 - 1600=-1431 \\ \\and \ we \ know \ when \ \Delta \ is \ negative, \ theres \ no \solution$

$4.\\ \\z^2-3z=0 \\ \\ (z-3)=0\\ \\z=0 \ \ \ or \ \ \ z-3 =0\ \ |+3\\ \\ z-3+3=0+3\\ \\z=0 \ \ \ or \ \ \ z=3$

$5.\\ \\q^2+7q=0 \\ \\q(q+7)=0\\ \\q=0 \ \ \ or \ \ \ q+7 =0\ \ |-7\\ \\q+7-7=0-7\\ \\q=0 \ \ \ or \ \ \ q=-7$

$6.\\ \\k^2+2k=0\\ \\k(k+2)=0\\ \\k=0 \ \ \ or \ \ \ k+2 =0\ \ |-2\\ \\k+2-2=0-2\\ \\k=0 \ \ \ or \ \ \ k=-2$

$7. \\ \\ x^2-3x-70=0 \\ \\a=1,\ b=-3, \ c=-70 \\ \\\Delta =b^2-4ac = (-3)^2-4\cdot 1\cdot (-70)= 9+280=289\\ \\ x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{3-\sqrt{289}}{2 }=\frac{ 3-17}{2}=\frac{-14}{2}=-7$

$x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{3+\sqrt{289}}{2 }=\frac{ 3+17}{2}=\frac{20}{2}=10\\ \\(x+7)(x-10)=0$

$8.\\ \\q^2+7q-60=0 \\ \\a=1,\ b=7, \ q=-60 \\ \\\Delta =b^2-4ac = 7^2-4\cdot 1\cdot (-60)=49+240=289 \\ \\ x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{-7-\sqrt{289}}{2 }=\frac{ -7-17}{2}=\frac{-24}{2}=-12$

$x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{-7+\sqrt{289}}{2 }=\frac{ -7+17}{2}=\frac{ 10}{2}= 5\\ \\(x+12)(x-5)=0$

$9.\\ \\z^2+9z-36=0 \\ \\a=1,\ b=9, \ q=-36 \\ \\\Delta =b^2-4ac = 9^2-4\cdot 1\cdot (-36)= 81+144=225\\ \\ x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{-9-\sqrt{225}}{2 }=\frac{ -9-15}{2}=\frac{-24}{2}=-12$

$x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{-9+\sqrt{225}}{2 }=\frac{ -9+15}{2}=\frac{6}{2}=3\\ \\(x+11)(x-3)=0$

$10.\\ \\d^2-13d+22=0 \\ \\a=1,\ b=-13, \ q=22 \\ \\\Delta =b^2-4ac = (-13)^2-4\cdot 1\cdot 22= 169-88=81\\ \\ d_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{13-\sqrt{81}}{2 }=\frac{ 13-9}{2}=\frac{4}{2}=2$

$d_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{13+\sqrt{81}}{2 }=\frac{ 13+9}{2}=\frac{22}{2}=11\\ \\(d-2)(d-11)=0$

7 0

3 years ago

Solve the equation 5.5(x-3)=17+10.5 in systems of equations. How can you find your solution?

Readme [11.4K]

Answer:

x= 8

Step-by-step explanation:

5.5(x-3)=17+10.5

5.5x - 16.5= 27.5

5.5x= 44

x= 8

3 0

3 years ago

I’m confuse plz help

Ad libitum [116K]

Answer:

As in an equilateral triangle all sides are equal so 9+3x = 5x-5

9+3x = 5x-5

9+5 = 5x-3x

14 = 2x

14/2 = x

7= x

So,As we know that x is 15 so we can substitute the values 9+3x or 5x-5

9+3x

=9+3*7

=30

So, one side of the triangle = 30

Perimeter of an equilateral triangle = 3*side

=3*30 = 90

So, perimeter of the equilateral triangle = 90

6 0

3 years ago

What is the value of the expression (-8/9) + (-2/3) x (-4 1/2)

geniusboy [140]

$\frac{4}{9}$

I hope this this is what you need ..

6 0

3 years ago

The center of a circle is at (-5 12) and it has a radius of 16. what is the equation of the circle?

Naya [18.7K]

Answer:

(x+5)^2+(y-12)^2=256

Step-by-step explanation:

Comparing the given (x+5)^2+(y-12)^2=256

to (x - h)^2 + (y - k)^2 = r^2,

we see that h must be -5, k must be 12 and r must be 16. This is the desired equation of the circle with center at (-5, 12) and radius 16.

4 0

3 years ago