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kati45 [8]
3 years ago
12

HELP!!!

Mathematics
1 answer:
umka2103 [35]3 years ago
4 0
I think the is c 14.1
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432 square feet 2/3 is with what's the length
Radda [10]
432 divide by 3. then multiply by two equals 288.
3 0
3 years ago
PLEASE ANSWER ASAP, WILL GIVE BRAINLIEST IF CORRECT
emmasim [6.3K]

If x > 0 then |x|/x = 1 !!!

If x<0 then |x|/x = -1

*below is an explanation! :)

_______________________________________

- I found the answer to this by choosing a any number that satisfies the requirement of x > 0 and plugging it into |x|/x  

-----

Watch this!

Let's take 10 for example. 10 is greater than 0 like x>0 requires!

Let's plug it into |x|/x

|10| ÷ 10 = 1

*Remember that | | this means "absolute value" or whatever is in between the two bars will always be positive (+)

-------

Now let's take a random number that satisfies 0> x and do the same as we did above!

Let's take -3 and plut it into |x|/x

|-3| ÷ -3 = -1

8 0
2 years ago
Read 2 more answers
Write the equation of a line that passes through (-4,15) and (-7,10) in point slope form
Ivanshal [37]
(-4,15),(-7,10)
slope = (10 - 15) / (-7 - (-4) = -5 / (-7 + 4) = -5 / -3 = 5/3

there can be 2 answers to this...depending on the point u use...
y - y1 = m(x - x1)
slope(m) = 5/3
using point (-4,15)...x1 = -4 and y1 = 15
now we sub
y - 15 = 5/3(x - (-4)..not done yet
y - 15 = 5/3(x + 4) <=== this is one answer

y - y1 = m(x - x1)
slope(m) = 5/3
using point (-7,10)....x1 = -7 and y1 = 10
now we sub
y - 10 = 5/3(x - (-7)...not done yet
y - 10 = 5/3(x + 7) <=== and here is the other answer
8 0
3 years ago
As the sample size becomes larger, the sampling distribution of the sample mean approaches a _____. a. binomial distribution b.
kkurt [141]

Answer:

c. normal probability distribution

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

By the Central Limit Theorem, it is a normal distribution, so option c.

7 0
2 years ago
Number 11. It's solving equations containing parentheses and having the variable in both sides.
Zielflug [23.3K]
11.\\\\2(6d+3)=18-3(16-3d)\\\\12d+6=18-48+9d\\\\12d-9d=18-48-6\\\\3d=-36\\\\d=-12
3 0
3 years ago
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