HELP!!!

vlabodo [156]

The blank space is found by dividing 36a^2 by 12, which is equal to 3a^2
To get to this answer you need to
1. divide the both sides of the equation by 12.
2. subtract 2b^2 from both sides.
You will see that the blank space equals 3a<span>^2 then</span>

7 0

3 years ago

The telephone company purchased 192 yards of wire for $2,304 in January. They

Aleks [24]

Answer:

Step-by-step explanation:

400yd($2304/192yd)=$4800

6 0

3 years ago

Read 2 more answers

There are three motors available to repair Ralph’s vacuum cleaner. Motor #1 has a 65% chance of breaking by the end of the week.

Orlov [11]

Answer:

0.619

Step-by-step explanation:

from the question we have the following data:

probability of motor 1 breaking = 65% = 0.65

probability of motor 2 breaking = 35% = 0.35

probability of motor 3 breaking = 5% = 0.05

since we have 3 motors the probability of any of them breaking down is = $\frac{1}{3}$

but what the question requires from us is the conditional probability of the first one being installed

we have to solve this questions using bayes theorem

such that:

$\frac{0.65*\frac{1}{3} }{0.65*\frac{1}{3}+0.35*\frac{1}{3}+0.05*\frac{1}{3} }$

= $\frac{0.2167}{0.2167+0.1167+0.0167}$

= $\frac{0.2167}{0.3501}$

= 0.618966

approximately 0.619

therefore the conditional probability ralph installed the first motor is 0.619

8 0

3 years ago

In the figure below, BCA ~ STR. Find cos C, sin C, and tan C. Round your answers to the nearest hundredth.

arsen [322]

Answer:

$\sin C\approx0.85\\\\\cos C \approx0.52\\\\\tan C\approx1.63$

Step-by-step explanation:

According to the trigonometric ratios in aright triangle :

$\sin x =\dfrac{\text{Side opposite to x}}{\text{Hypotenuse}}\\\\\cos x =\dfrac{\text{Side adjacent to x}}{\text{Hypotenuse}}\\\\\tan x=\dfrac{\sin x}{\cos x}$

Given: ΔBCA ~ ΔSTR

Since , corresponding angles of two similar triangles are equal.

So, ∠C = ∠T ...(i) [Middle letter]

In triangle STR

$\sin T=\dfrac{\text{Side opposite to T}}{\text{Hypotenuse}}\\\\=\dfrac{26.4}{30.9}\approx0.85\\\\\cos x =\dfrac{\text{Side adjacent to T}}{\text{Hypotenuse}}\\\\=\dfrac{16.2}{30.9}\approx0.52\\\\\tan T=\dfrac{\sin T}{\cos T}\\\\=\dfrac{0.85}{0.52}\approx1.63$ ...(ii)

From (i) and (ii), we have

$\sin C\approx0.85\\\\\cos C \approx0.52\\\\\tan C\approx1.63$

4 0

4 years ago

I'll show a pic of my question

Hunter-Best [27]

Answer:

Umm I think you forgot to send the pic with this question

Step-by-step explanation:

Hope I can help next time!!!!!!

7 0

3 years ago