L(x) = 2(2x + 1)3(2 – 2x)3 Leading term!!

1 answer:

4 0

The leading term is 18, since the term on the right can be simplifies to 18(2x+1)(2-2x). 18 is the first term in the sequence.

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After raining for 34 of an hour, a rain gauge is 25 filled. If it continues to rain at that rate for 15 more minutes, what fract

ivann1987 [24]

Answer:

$\textbf{Fraction of gauge filled = }\bf\frac{8}{15}$

Step-by-step explanation:

This equation does not represent the situation because to find the fraction of the rain gauge we need to : divide the fraction of gauge filled by the raining fraction of an hour

But, Diego wrote the incorrect division equation so, it does not represent the current situation.

Now, to find the required division and multiplication equations :

$\frac{3}{4}\text{ fraction of an hour = }\frac{3}{4}\times 60=\text{ 45 minutes}\\\\\text{ Now, the rain continues to rain for 15 minutes more}\\\implies \text{The total raining time = 45 + 15 = 60 minutes}\\\\\text{So, we need to find the fraction of gauge filled in 60 minutes}\\\\\text{Fraction of gauge filled in 45 minute = }\frac{2}{5}\\\\\text{Fraction of gauge filled in 1 minute = }\frac{\frac{2}{5}}{45}=\frac{2}{5\times 45}\\\\\text{Fraction of gauge filled in 60 minutes = }\frac{2}{5\times 45}\times 60=\bf\frac{8}{15}$

$\text{Division equation = }\frac{\text{fraction of gauge filled}}{\text{raining fraction of an hour}}\\\\\textbf{Division Equation : }\frac{\frac{2}{5}}{\frac{3}{4}}=\frac{2}{5}\times \frac{4}{3}=\frac{8}{15}\\\\\text{Multiplication Equation = Fraction of gauge filled in 1 minute × 60}\\\\\textbf{Multiplicatiuon Equation : }\frac{2}{225}\times 60=\frac{8}{15}$