5c^5 + 60c^4 + 180c^3
find the GCF, 5c³
5c³(5c^5 + 60c^4 + 180c^3/ 5c^3)
5c³(c² + 12c + 36)
5c³(c² + 2(c)(6) + 6²)
5c³(c + 6)² <<< the answer.
hope this helps, God bless!
Answer:
any # where -2<=x<7
Step-by-step explanation:
(x-7) would be negative and (x+3) positive, resulting in f(x) being negative.
Hello from MrBillDoesMath!
Answer:
a(n) = (-n)^3 where n = 1,2,3,...
Discussion:
The pattern 1,8,27, 64... is immediately recognizable as the the cube of the positive integers. But this question has a minus sign appearing before each entry, suggesting we try this:
- 1 = (-1)^3
-8 = (-2)^3
-27 = (-3)^3
-64 = (-4)^3
That's what the problem statement asked for
. The answer is equivalently
-1 * (n^3)
Thank you,
MrB
1 bag=2cups. so, he uses 1 and 0.25 bags. there are 3.75 bags left. hope that helps)