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patriot [66]
3 years ago
5

Choose the correct slope of the line that passes through the points (1, −3) and (3, −5).

Mathematics
2 answers:
kotegsom [21]3 years ago
7 0

Answer:

the answer is a

Step-by-step explanation:

Flura [38]3 years ago
4 0
Slope of a line passing though point (x1,y1) nd (x2,y2) is
(y2-y1)/(x2-x1)

we have
(1,-3) and (3,-5)
x1=1
y1=-3
x2=3
y2=-5

slope=(-5-(-3))/(3-1)=(-5+3)/(2)=-2/2=-1

slope=-1
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What is cos theta when sin theta = sqrt 2/3
Fittoniya [83]

<u>Answer:</u>

Value of cosθ is ±√7/3 .

<u>Step-by-step explanation:</u>

According to the Question , value of :

\red{\implies sin\theta = \dfrac{\sqrt2}{3}}

And , we know the identity of sine and cosine as ,

\boxed{\pink{\sf\implies sin^2\theta + cos^2\theta = 1} }

<u>Using</u><u> </u><u>,</u><u> </u><u>this</u><u> </u><u>ident</u><u>ity</u><u> </u><u>we</u><u> </u><u>have</u><u> </u><u>;</u><u> </u>

\implies sin^2\theta + cos^2\theta = 1 \\\\\implies \bigg( \dfrac{\sqrt2}{3}\bigg)^2 + cos^2\theta = 1 \\\\\implies \dfrac{2}{9} + cos^2\theta = 1 \\\\\implies cos^2\theta = 1 - \dfrac{2}{9} \\\\\implies cos^2\theta = \dfrac{9-2}{9} \\\\\implies cos\theta = \sqrt{\dfrac{7}{9}} \\\\\underline{\boxed{\blue{\bf \implies cos\theta = \pm \dfrac{\sqrt 7 }{3}}}}

Now , here since θ is in 2nd quadrant and in 2nd quadrant cos is negative . Hence ,the value of cos will be :

\boxed{\orange{\bf \implies cos\theta =-\dfrac{\sqrt7}{3}}}

3 0
3 years ago
Help me with this question this was supposed to be due yesterday!
Inessa05 [86]

Answer: Both the mean and median decreased.

Step-by-step explanation:

The addition of the 500 lb baby elephant will have a huge impact on the mean, since you'll be finding the average (adding all numbers then dividing). So the only logical answer would be the chosen. The median will most likely either decrease or stay the same, but since staying the same isn't an option for the median, it's most likely going to be decrease.

[I do apologize in advance if it's wrong, and next time try submitting work on time :)) Hope I helped!]

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