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patriot [66]
3 years ago
5

Choose the correct slope of the line that passes through the points (1, −3) and (3, −5).

Mathematics
2 answers:
kotegsom [21]3 years ago
7 0

Answer:

the answer is a

Step-by-step explanation:

Flura [38]3 years ago
4 0
Slope of a line passing though point (x1,y1) nd (x2,y2) is
(y2-y1)/(x2-x1)

we have
(1,-3) and (3,-5)
x1=1
y1=-3
x2=3
y2=-5

slope=(-5-(-3))/(3-1)=(-5+3)/(2)=-2/2=-1

slope=-1
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What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
Sati [7]

<u>Answer-</u>

<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>

<u>Solution-</u>

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are  J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117

As,

\Rightarrow 117=81+36

\Rightarrow JL^2=JK^2+KL^2

\Rightarrow \text{JKL is a right angle triangle}

\Rightarrow \angle K=90^{\circ}

Therefore, the vertex at K (-4, 8) is the orthocentre.

3 0
3 years ago
Determine the value of the first term and write a recursive definition for the following
Marysya12 [62]
It is just counting by 5.
5 0
3 years ago
I need help simplifying this
faust18 [17]

Answer:

n^2

Step-by-step explanation:

cancel the common factor between n^7 and n^2

3 0
3 years ago
Sheila rolled a number cube numbered 1 through 6 and tossed a coin for heads, H, or tails, T.
Romashka [77]
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3 years ago
Determine the sum -46.38 (-24.6)
Zarrin [17]
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I hope this helps, and have a fantastic day!
8 0
3 years ago
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