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Taya2010 [7]
2 years ago
15

The diameter of circle X is 15 centimeters. The diameter of circle Y is 20 centimeters. Which measurement is closest to the diff

erence between the circumference of circle X and the circumference of circle Y in centimeters?
Mathematics
2 answers:
valina [46]2 years ago
8 0

The difference between the circumference of circle X and circumference of circle Y is 5π cm.

<h3>What is circumference of a circle?</h3>

This is the distance round a circle.

The circumference of circle X is calculated as follows;

C_X = \pi d\\\\&#10;C_X = 15\pi \ cm

The circumference of circle Y is calculated as follows;

C_Y = \pi d\\\\&#10;C_Y = 20 \pi \ cm

The difference between the circumference of circle X and circumference of circle Y is calculated as follows;

C_Y - C_X = 20\pi - 15 \pi = 5\pi \ cm \\\\&#10;

Thus, the difference between the circumference of circle X and circumference of circle Y is 5π cm.

Learn more about circumference of  a circle here: brainly.com/question/9782777

sp2606 [1]2 years ago
5 0

Using the formula for the circumference, it is found that the difference between the circumference of circle X and the circumference of circle Y is of 31.4 centimeters.

<h3>What is the measure of the circumference of a circle?</h3>
  • The circumference of a circle of radius r is given by:

C = 2\pi r

The diameter of circle X is 15 centimeters, hence r = 15 and:

C_X = 2\pi(15) = 30\pi

The diameter of circle Y is 20 centimeters, hence r = 20 and:

C_Y = 2\pi(20) = 40\pi

Then, the difference, in centimeters, is of:

d = C_X - C_Y = 40\pi - 30\pi = 10\pi = 31.4

You can learn more about circles at brainly.com/question/17326298

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Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -
GaryK [48]

Consider all parabolas:

1.

y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

2.

y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

3.

y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

4.

y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

5.

y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

6.

y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.

3 0
3 years ago
If EF=9x+14, FG=56, and EG=250, find the value of x.
nexus9112 [7]

Answer:

Value of x =20

Step-by-step explanation:

Given: EF = 9x+14 units , FG = 56 units and EG = 250 units.

Segment Addition Postulates states the following for 3 points that are collinear.

i.e, Let three points A, B and C are collinear and B is between A and C.

i,e AC = AB + BC

By Segment addition postulates; solve for x;

EG = EF + FG

Substitute the given values we get;

250 = 9x + 14 + 56

or

250 = 9x + 70

Subtract 70 on both sides we get;

250 -70 = 9x + 70 -70

Simplify:

180 = 9x

Divide both sides by 9 we get;

\frac{180}{9} = \frac{9x}{9}

Simplify:

x = 20

Therefore, the value of x =20


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3 years ago
I need help please I would really appreciate it
Alchen [17]

Answer:

Your answer to the fig. would be 14cm^2.

Adding area of both rectangles,

(8+6) cm^2

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Which is the simplified form of (9c^-9)-3
Orlov [11]

3[3c^(-9)-1]

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3 years ago
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