4-3 is correct glad to help
<h3>There are 76 nickels in jar</h3>
<em><u>Solution:</u></em>
Let "d" be the number of dimes
Let "n" be the number of quarters
1 dime = $ 0.10
1 nickel = $ 0.05
There are 140 coins in the jar
Therefore,
d + n = 140
n = 140 - d ------- eqn 1
Lee has $10.20 in a jar that contains only nickels and dimes
Therefore,

0.1d + 0.05n = 10.20 -------- eqn 2
<em><u>Substitute eqn 1 in eqn 2</u></em>
0.1d + 0.05( 140 - d) = 10.20
0.1d + 7 - 0.05d = 10.20
0.05d = 3.2
Divide both sides by 0.05
d = 64
<em><u>Substitute d = 64 in eqn 1</u></em>
n = 140 - 64
n = 76
Thus there are 76 nickels in jar
The answer is 8 × 10² km.
Volume of the cube with edge a is: V = a³
1 mole = V = a³
1 mole = 6.02 × 10²³ cm³
a = ?
a = ∛6.02 × 10²³ cm³ = 84 436 877 cm
1 km = 1 000 000 cm
1 cm = 0.000001 km
a = 84 436 877 cm = 844 km = 8.44 × 100 km = 8.44 × 10² km ≈ 8 × 10² km
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