Literal equation is an equation where variables represent known values. Literal equations allow use to represent things like distance, time, interest, and slope as variables in an equation.
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
The relationship is proportional.
The relationship is linear.
The equation of the line is y = –3x.
Step-by-step explanation:
The line in the question passes through origin and (4,-12).
The rate of change of the line is

The rate of change of the line or slope of the line is -3
Equation of the line is given by

This means that the relationship is linear.
If we take any value of x then there will be only one value of y this means that the relationship is proportional.
So the following statements are true
The relationship is proportional.
The relationship is linear.
The equation of the line is y = –3x.
Answer:
-
Step-by-step explanation:
Rule for rounding :
You look at the number next to the place value you are meant to round and if the number is :
=
4 and below you round down.
5 and above you round up
Nearest hundred thousand: 100,000
This is because you look at the number next to the hundred thousand spot which is a 2 so you round down
Nearest ten thousand: 130,000
Same reason as before the number next to the 2 in the number is a 6. So you round up
Nearest thousand: 126,000
The number next to the thousandth place value is a 0 so you round down