All categories

3 years ago

Select all equations where r=3 is a solution

Mathematics

1 answer:

belka [17]3 years ago

5 0

Answer:

the first equation

Step-by-step explanation:

You might be interested in

Graph the function. For the function whose graph is shown below, which is the correct formula for the function? y = –x – 1 y = x

rusak2 [61]

You forgot to mention the graph.
So, I make the graph of both given functions and you will compare your graph with them.

First, y= -x-1
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,-1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.

Second, y= x+1
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.

4 0

3 years ago

etta bought a calculator for $15. Glenn found the same model for $9.79. How much more did Etta pay than Glenn

ololo11 [35]

5.21.

To find this, give both numbers decimal points before setting up a subtraction equation as so:

15.00 - 9.79

Then proceed to solve to get the final answer of 5.21.

Hope this helps!

6 0

3 years ago

Read 2 more answers

Which of the following is the rational exponent expression of third root of 4 n? A) (4n)3

zhuklara [117]

You have to check which of the following expressions is the rational exponent expression of third root of 4n, or mathematically, $\sqrt[3]{4n} .$ Consider all cases:

A. $(4n)^3=4^3\cdot n^3=64n^3\neq\sqrt[3]{4n} .$

B. $3n^4\neq \sqrt[3]{4n} .$

C. quantity of 4n to the one third power is $(4n)^{\frac{1}{3} }=\sqrt[3]{4n}$ (by the definition of rational power).

D. 4 times n to the one third power is $4\cdot n^{\frac{1}{3} }=4\sqrt[3]{n}\neq \sqrt[3]{4n} .$

Answer: correct choice is C.

3 0

3 years ago

Read 2 more answers

Solve for x in simplest form. 14 = 1/3(8x + 6)

elena-s [515]

Answer:

x = 4.5

Step-by-step explanation:

14 = 8/3x + 2

12 = 8/3x

36 = 8x

x = 4.5

5 0

3 years ago

What is the constant term of the quotient when 2x^3-3x^2 + 4x-2 is divided by x^2-x+2?

AlladinOne [14]

Answer:

-1

Step-by-step explanation:

See the attachment for the polynomial long division. The constant in the quotient is -1.

_____

Here, there is a remainder of -x. If there were no remainder the constant in the quotient is the ratio of the constant in the dividend to the constant in the divisor: -2/2 = -1.

That could be a first guess in a "guess and check" solution approach.

Guess: first term of binomial quotient is (2x^3)/x^2 = 2x; last term of binomial quotient is -2/2 = -1. So, the quotient is guessed to be (2x -1).

Check: (2x -1)(x^2 -x +2) = 2x^3 -3x^2 +5x -2

Subtracting this from the actual dividend gives a remainder of -x. This has a lower degree than the divisor, so no further adjustment of the quotient is required.

6 0

3 years ago