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3 years ago

Help me please then I will give point

Mathematics

2 answers:

pav-90 [236]3 years ago

6 0

Answer:

D (3,2) and (5,4)

Step-by-step explanation:

Co-ordinates are in the form (x,y), so for each pair, the second figure should be one digit less than the first one. The only option that satisfies this is D.

almond37 [142]3 years ago

4 0

the answer is b

Step-by-step explanation:

x comes before y so the second number EX: (3,1) the number 1 would be y and same with (5,1) in answer b both of them would be less than y

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The image of the point (4,-2) under a rotation 180 degrees about the origin is: A. (−4,−2) B. (−4,2) C. (−2,−4) D. (−2,4)

Arlecino [84]

Answer:

(-4,2)

Step-by-step explanation:

when rotated about 180 degrees, you change both signs

6 0

3 years ago

Zoom in to see the question do anybody know ?

olga2289 [7]

Answer:

1 or I

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Please Help. Thank you

jeyben [28]

The answer is D. A translation does not change a figure's size or shape because each of its points are moved the same amount and in the same direction(s).

8 0

3 years ago

A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u

Kryger [21]

Given: $f(x) = \frac{1}{x-2}$

$g(x) = \frac{2x+1}{x}$

A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

$f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}$

$f(\frac{2x+1}{x} )=\frac{x}{1}$

$f(\frac{2x+1}{x} )=1$

Also,

$g(f(x))= g(\frac{1}{x-2} )$

$g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{x }{1}$

$g(\frac{1}{x-2} )= x$

Since, $f(g(x))=g(f(x))=x$

Therefore, both functions are inverses of each other.

For the Composition function $f(g(x)) = f(\frac{2x+1}{x} )=x$

Since, the function $f(g(x))$ is not defined for $x=0$ .

Therefore, the domain is $(-\infty,0)\cup(0,\infty)$

For the Composition function $g(f(x)) =g(\frac{1}{x-2} )=x$

Since, the function $g(f(x))$ is not defined for $x=2$ .

Therefore, the domain is $(-\infty,2)\cup(2,\infty)$

8 0

3 years ago

Subtract the equations.

Lostsunrise [7]

Answer:

0x+2y=22

Step-by-step explanation:

Set them equal to each other, (5x+4y=25)-(5x+2y=3). Distribute the negative into the right equation, (5x+4y=25)(-5x-2y=-3). Then combine like terms to get your answer.

6 0

3 years ago