Answer:
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The domain for x is all real numbers greater than zero and less than 5 com
Step-by-step explanation:
<em><u>The question is</u></em>
What is the volume of the open top box as a function of the side length x in cm of the square cutouts?
see the attached figure to better understand the problem
Let
x -----> the side length in cm of the square cutouts
we know that
The volume of the open top box is
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we have
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

substitute
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Find the domain for x
we know that
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so
The domain is the interval (0,5)
The domain is all real numbers greater than zero and less than 5 cm
therefore
The volume of the open top box as a function of the side length x in cm of the square cutouts is
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Answer:
Probability is O %
Step-by-step explanation:
Answer:
Step-by-step explanation:
look at 2=x-y=2
move this term to the left (2)
it becomes 2=x-y+2=0
and thats your results
Examples: x^2-2x=-1, 3x-x-x+a-a=5, (x^2-1)/(x+1), 2x-(x+x)
Answer:
The side closest to P is the side that is on the same side of the angle bisector as P.
Step-by-step explanation:
The angle bisector is the line containing all the points equidistant from the sides of the angle. Points on one side of the angle bisector are closer to the angle side that is on that side of the angle bisector.
___
The attached diagram shows the angle bisector as a dashed line. A couple of different locations for P are shown (P1 and P2). Apparently, we're concerned here with the distance from P along the perpendicular to each side of the angle. For P2 (on the left side of the angle bisector), it may be clear that the left perpendicular is shorter than the right one. Likewise, for P1, the right perpendicular will be shorter.
Answer:
1, 4, 9, 16,25, 36, 49, 64, 81, 100, 121, 144
Step-by-step explanation: hope it helps