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3 years ago

8

latest between two digit number and the number obtained by interchanging the position of its digit is 36 what is the difference

between the two digit number

2 answers:

Jet001 [13]3 years ago

7 0

9514 1404 393

Answer:

4

Step-by-step explanation:

We assume you're asking the difference between the digits of a two-digit number such that reversing the digits makes the value different by 36.

The difference between the digits is 36/9 = 4.

__

The value difference is always 9 times the digit difference.

More information on this subject can be found at brainly.com/question/22693620

rjkz [21]3 years ago

6 0

Answer:

the answer is 4

Step-by-step explanation:

:)))))))

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32% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a

Tems11 [23]

Answer:

a) $P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

b) $P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

c) $P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816$

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=10, p=0.32)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

Part b

$P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]$

$P(X=0)=(10C0)(0.32)^0 (1-0.32)^{10-0}=0.0211$

$P(X=1)=(10C1)(0.32)^1 (1-0.32)^{10-1}=0.0995$

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

$P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

Part c

$P(2 \leq x \leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)$

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

$P(X=3)=(10C3)(0.32)^3 (1-0.32)^{10-3}=0.264$

$P(X=4)=(10C4)(0.32)^4 (1-0.32)^{10-4}=0.218$

$P(X=5)=(10C5)(0.32)^5 (1-0.32)^{10-5}=0.123$

$P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816$

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Find the slope of the line that passes through the points (−2/3, 3/4) and (5/6, −1/2).

EastWind [94]

Answer:

$-\frac{5}{6}$

Step-by-step explanation:

Use the slope formula : $\frac{y2-y1}{x2-x1}$

-1/2 is y2, 3/4 is y1, 5/6 is x2, and -2/3 is x1.

$\frac{-1/2-3/4}{5/6-(-2/3)}$

$\frac{-5/4}{5/6+2/3}$

$\frac{-5/4}{9/6}$

$\frac{-5}{4}$ ÷ $\frac{9}{6}$

$-\frac{5}{4}$ • $\frac{6}{9}$

$-\frac{5}{2}$ • $\frac{3}{9}$

$-\frac{15}{18}$

$-\frac{5}{6}$

Hope this helps! Let me know if I got it wrong.

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Answer:

Here is the solution...hope it helps:)

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It is approximately 1830.

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