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2 years ago

8

latest between two digit number and the number obtained by interchanging the position of its digit is 36 what is the difference

between the two digit number

2 answers:

Jet001 [13]2 years ago

7 0

9514 1404 393

Answer:

4

Step-by-step explanation:

We assume you're asking the difference between the digits of a two-digit number such that reversing the digits makes the value different by 36.

The difference between the digits is 36/9 = 4.

__

The value difference is always 9 times the digit difference.

More information on this subject can be found at brainly.com/question/22693620

rjkz [21]2 years ago

6 0

Answer:

the answer is 4

Step-by-step explanation:

:)))))))

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a. A 2017 poll found that 56% of college students were very confident that their major will lead to a good job. If 15 college s

lesya [120]

Answer:

0.01083 or 1.083%

Step-by-step explanation:

This problem can be modeled as a binomial probability model with probability of success p = 0.56.

The probability of x=13 successes (a college student being very confident their major would lead to a good job) in a number of trials of n=15 is:

$P(X=x) = \frac{n!}{(n-x)!x!} *p^x*(1-p)^{n-x}\\P(X=13) = \frac{15!}{(15-13)!13!} *0.56^{13}*(1-0.56)^{15-13}\\P(X=13) = 0.01083=1.083\%$

The probability is 0.01083 or 1.083%.

8 0

2 years ago

Given P = x^0.3 y^0.7 is the chicken lay eggs production function, where P is the number of eggs lay, x is the number of workers

lora16 [44]

Answer:

Part A)

$\displaystyle \frac{dy}{dx}=-\frac{3}{7}P^\frac{10}{7}x^{-\frac{10}{7}}$

Part B)

The daily operating cost decreases by about $143 per extra worker.

Step-by-step explanation:

We are given the equation:

$\displaystyle P=x^{\frac{3}{10}}y^{\frac{7}{10}}$

Where <em>P</em> is the number of eggs laid, <em>x</em> is the number of workers, and <em>y</em> is the daily operating budget (assuming in US dollars $).

A)

We want to find dy/dx.

So, let’s find our equation in terms of <em>x</em>. We can raise both sides to 10/7. Hence:

$\displaystyle P^\frac{10}{7}=\Big(x^\frac{3}{10}y^\frac{7}{10}\Big)^\frac{10}{7}$

Simplify:

$\displaystyle P^\frac{10}{7}=x^\frac{3}{7}y$

Divide both sides by<em> </em>the <em>x</em> term to acquire:

$\displaystyle y=P^\frac{10}{7}x^{-\frac{3}{7}}$

Take the derivative of both sides with respect to <em>x: </em>

$\displaystyle \frac{dy}{dx}=\frac{d}{dx}\Big[P^\frac{10}{7}x^{-\frac{3}{7}}\Big]$

Apply power rule. Note that P is simply a constant. Hence:

$\displaystyle \frac{dy}{dx}=P^\frac{10}{7}(-\frac{3}{7})(x^{-\frac{10}{7}})$

Simplify. Hence, our derivative is:

$\displaystyle \frac{dy}{dx}=-\frac{3}{7}P^\frac{10}{7}x^{-\frac{10}{7}}$

Part B)

We want to evaluate the derivative when <em>x</em> is 30 and when <em>y</em> is $10,000.

First, we will need to find <em>P</em>. Our original equations tells us that:

$P=x^{0.3}y^{0.7}$

Hence, at <em>x</em> = 30 and at <em>y</em> = 10,000, <em>P </em>is:

$P=(30)^{0.3}(10000)^{0.7}$

Therefore, for our derivative, we will have:

$\displaystyle \frac{dy}{dx}=-\frac{3}{7}\Big(30^{0.3}(10000^{0.7})\Big)^\frac{10}{7}\Big(30^{-\frac{10}{7}}\Big)$

Use a calculator. So:

$\displaystyle \frac{dy}{dx}=-\frac{1000}{7}=-142.857142...\approx-143$

Our derivative is given by dy/dx. So, it represents the change in the daily operating cost over the change in the number of workers.

So, when there are 30 workers with a daily operating cost of $10,000 producing a total of about 1750 eggs, the daily operating cost decreases by about $143 per extra worker.

5 0

2 years ago

What are the solutions of 3(x – 4)(2x – 3) = 0? Check all that apply.

RSB [31]

The answer will 3/2 and 4 :)

8 0

3 years ago

Read 2 more answers

There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro

elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that $\mu = 20.1, \sigma = 5.1$ .

You scored 24 on Exam A. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{24 - 20.1}{5.1}$

$Z = 0.76$

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that $\mu = 1031, \sigma = 215$ .

You scored 1167 on Exam B, s:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1167 - 1031}{215}$

$Z = 0.632$

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0

3 years ago

What number should be added to both sides of the equation to complete the square X2+3x=6

harina [27]

Answer:

add 6

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers