<h2>
![\huge \mathfrak \orange{Question}](https://tex.z-dn.net/?f=%20%5Chuge%20%5Cmathfrak%20%5Corange%7BQuestion%7D)
</h2>
Two bikers are riding a circular path.
The first rider completes a round in 12
minutes. The second rider completes
a round in 18 minutes. If they both
started at the same place and time
and go in the same direction, after
how many minutes will they meet
again at the starting point?
<h2>
![\huge \mathfrak \orange{Solution}](https://tex.z-dn.net/?f=%20%5Chuge%20%5Cmathfrak%20%5Corange%7BSolution%7D)
</h2>
![\huge \mathsf \blue{Given}](https://tex.z-dn.net/?f=%20%5Chuge%20%5Cmathsf%20%5Cblue%7BGiven%7D)
- First rider takes 12 minutes to complete a round.
- Second rider takes 18 minutes to complete a round.
![\huge \mathsf \blue{To\: Find}](https://tex.z-dn.net/?f=%20%5Chuge%20%5Cmathsf%20%5Cblue%7BTo%5C%3A%20Find%7D)
After how many minutes will they meet
again at the starting point?
Take the LCM of 12 and 18
12 = 2 × 2 × 3
18 = 2 × 3 × 3
Thus, the LCM of 12 and 18 is 36.
<h3>So they will meet after 36 minutes again at the starting point.</h3>
Yeah mate, but I don’t know if you need to specifically say but it’s actually an Amazon Prime next day delivery polynomial
Given:
![72-\frac{8}{2}+6\times3](https://tex.z-dn.net/?f=72-%5Cfrac%7B8%7D%7B2%7D%2B6%5Ctimes3)
He does mistake in the order of giving preference.
We should give preference in the order, division, multiplication, addition, subtraction.
But, he gave the first preferrence to the subtraction.
72-8=64
Next, he used division
64/2=32
Next he adds 32 with 8.
So, he gets 50.
But the actual simplification is,
Simplifying we get,
![\begin{gathered} 72-\frac{8}{2}+6\times3=72-4+18 \\ =68+18 \\ =86 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2072-%5Cfrac%7B8%7D%7B2%7D%2B6%5Ctimes3%3D72-4%2B18%20%5C%5C%20%3D68%2B18%20%5C%5C%20%3D86%20%5Cend%7Bgathered%7D)
Hence, the correct value of the expression is 86.
1. Write down the decimal divided by 1
2. Multiply both top and bottom by 10
3. Simplify the fraction.