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3 years ago

5

Kelsha purchased a prepaid phone card for $30. Long distance calls cost 21 cents a minute using this card. Kelsha used her card

only once to make a long distance call. If the remaining credit on her card is $22.44, how many minutes did her call last?

1 answer:

bagirrra123 [75]3 years ago

5 0

Answer:

2.646

Step-by-step explanation:

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For three consecutive years, Sam invested some money at the start of the year. The first year, he invested x dollars. The second

faust18 [17]

$\bf \stackrel{\textit{Sam invested the first year}}{x} \qquad \qquad \stackrel{\textit{2nd year is \$2,000 less than \underline{x}}}{x-2000} \\\\\\ \stackrel{\textit{3rd year is \$1,000 more than \underline{x}}}{x+1000}\qquad \qquad \boxed{\stackrel{\textit{Sam total investment}}{(x)+(x-2000)+(x+1000)}}\\\\ -------------------------------\\\\ \stackrel{\textit{Sally invested the first year \$1000 less than \underline{x}}}{x-1000}$

$\bf \stackrel{\textit{2nd year is \$1500 less than \underline{2x}}}{2x-15000}\qquad \qquad \stackrel{\textit{3rd year is \$1400 more than \underline{x}}}{x+1400} \\\\\\ \boxed{\stackrel{\textit{Sally total investment}}{(x-1000)+(2x-1500)+(x+1400)}}$

$\bf \stackrel{\textit{Sam total investment}}{(x)+(x-2000)+(x+1000)}=\stackrel{\textit{Sally total investment}}{(x-1000)+(2x-1500)+(x+1400)} \\\\\\ 3x-1000=4x-1100\implies 100=x\impliedby \textit{Sam invested the first year} \\\\\\ \stackrel{\textit{Sally invested last year}}{x+1400}\implies 10+1400\implies 1500$

4 0

4 years ago

Need help with number 7

padilas [110]

Answer:

hi there!

the correct answer to this question is: 24 crackers

Step-by-step explanation:

you add (2/5) and (1/5) together to get (3/5)

then you multiply 3/5 by 40 to get 24

6 0

3 years ago

Find x if ∠m1 = 2x + 10 and m∠2 = 3x - 6

icang [17]

Answer: 16

Step-by-step explanation:

3 0

2 years ago

A circle has a radius of \sqrt{13}√ 13 square root of, 13, end square root units and is centered at (-9.3,4.1)(−9.3,4.1)le

timofeeve [1]

Answer: The equation of the circle is

$x^2+y^2+18.6x-8.2y+90.3=0.$

Step-by-step explanation: We are given to write the equation of the circle with radius √13 units and center at the point (-9.3, 4.1).

We know that

the standard equation of a circle with radius r units and center at the point (h, k) is given by

$(x-h)^2+(y-k)^2=r^2.$

In the given circle,

radius, r = √13 units and center, (h, k) = (-9.3, 4.1).

Therefore, the equation of the circle will be

$(x-(-9.3))^2+(y-4.1)^2=(\sqrt{13})^2\\\\\Rightarrow (x+9.3)^2+(y-4.1)^2=13\\\\\Rightarrow x^2+18.6y+86.49+y^2-8.2y+16.81=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+103.3=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+90.3=0.$

Thus, the equation of the circle is

$x^2+y^2+18.6x-8.2y+90.3=0.$

7 0

3 years ago

Find the perimeter of the swimming pool

loris [4]

12+40+28+12= 92

40-12= 28

92+28= 120

28-12= 16

120+16= 136

P=136

5 0

4 years ago