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Maslowich
2 years ago
13

A central angle in a circle measures 120°. What is the measure of its intercepted arc?

Mathematics
2 answers:
Evgesh-ka [11]2 years ago
7 0
My answer came out to be 180.

nydimaria [60]2 years ago
4 0

120 is the measure of the intercepted arc.

Hope this helps :)

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What is 6 1/4 - 3 1/3
Anettt [7]
Hey There!

Remember, first find the gcf of 4,3 in this problem it is 12.

Steps to solve

1.6\frac{1}{4} - 3\frac{1}{3}

2.6\frac{1}{4} - 3 \frac{1}{3} = 2\frac{11}{12}

So, The answer is <span>2\frac{11}{12}</span>

Hope This Helps :)
6 0
3 years ago
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6 hats for $45 what was the cost per hat ​
Lera25 [3.4K]

Answer:

270

Step-by-step explanation:

you will times 6 by 45

8 0
2 years ago
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Who made an error? <br> The correct scale factor= ?
Ostrovityanka [42]

Answer:

reggie made an error

the correct scale factor is 2/3

Step-by-step explanation:

we want to get from A to A', B to B', and ultimately C to C'

to get there, we must multiply each value in each point by the scale factor.

let's start out with reggie's scale factor. he multiplies each value in C by 3/2 to get to C'. we can try this out with one point, e.g. A

for A: 3/2 * (-12, -6) = (-18, -9). this is not A' = (-8, -4)! thus, 3/2 cannot be the scale factor

now, onto hillary's scale factor of 2/3

for A: 2/3 * (-12, -6) = (-8, -4). this is A'! thus, hillary is correct and reggie made an error

the correct scale factor is thus hillary's: 2/3

4 0
2 years ago
Urve revolves around the x-axis. if you cannot evaluate the integral exactly, use your calculator to approximate it. (round your
Archy [21]

The value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Given the equation y=16-x^{2} and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16-x^{2} from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16-x^{2}

Find the integration of 16-x^{2}.

=16x-x^{3}/3

Now find the value of integration from x=-1 to x=1.

=16(1)-(1)^{3}/3-16(-1)-(-1)^{3}/3

=16(1)-1/3+16-1/3

=32-2/3

=(96-2)/3

=94/3

Hence the value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Learn more about integration at brainly.com/question/27419605

#SPJ4

4 0
1 year ago
Hitch equation is y=6x^2+12x-10 rewritten in vertex form?
kirill [66]
D)y=6(x+1)²-16= 6(x²+2x+1)-16= 6x²+12x+6-16= 6x²+12x-10

<span>answer: D</span>
4 0
3 years ago
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