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Evgen [1.6K]
4 years ago
7

Required information NOTE: This is a mult-part Once an answer is submitted, you will be unable to return to this part Consider a

positive integer n Put the steps in cortect order to prove that if n is even, then 7n+ 4 is even (You must provide an answer before moving to the next part) es Rank the options below This is 2 times an integer, so it is even Since n is even, it can be written as 2k for some integer k Then 7n+ 414k+ 4-2(7k+ 2)
Mathematics
1 answer:
Arisa [49]4 years ago
6 0

Answer with Step-by-step explanation:

Suppose a positive integer n.

We have to prove that if n is even , then 7n+4 is even .

We are given some steps in order to prove this we have to arrange in correct order.

If n is even, it can be written as 2k

n=2k  for some integer k

Then substitute the value of n then we get

7(2k)+4

14k+4

2(7k+2)

This is 2 times an integer , so it is even.

Hence, proved.

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