3 years ago

I need help 1 through 5 for now

Mathematics

1 answer:

bazaltina [42]3 years ago

6 0

1. 3x
2. x
3. 6x
4. 3x
5. 6x

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2х - Зу = -4 -5х + 9y=7

Pani-rosa [81]

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3 years ago

Given the equation Square root of 2x plus 1 = 3, solve for x and identify if it is an extraneous solution. x = 4, solution is ex

Darya [45]

$\text{The domain:}\\2x+1\geq0\to 2x\geq-1\to x\geq-0.5\\\\D:x\geq0.5\to x\in\left\ \textless \ 0.5;\ \infty\right)\\\\\sqrt{2x+1}=3\ \ \ \ |\text{square both sides} \\2x+1=3^2\\2x+1=9\ \ \ |-1\\2x=8\ \ \ \ |:2\\x=4\in D\\\\\text{Answer: x =0, solution is not extraneous}.$