<span>Ending Amt = Bgng Amt * e ^-0.03t
In this equation, the "-0.03" is the decay factor or "k"
We can now solve for half-life by this equation:
</span>t = <span>(<span>ln [y(t) ÷ a]<span>)<span> ÷ -k (we can say beginning amount = 200 and ending amount = 100
</span></span></span></span>t = <span>(<span>ln [200 ÷ 100]<span>)<span> ÷ -k
</span></span></span></span>t = <span>(<span>ln [2]<span>)<span> ÷ -k
</span></span></span></span>t = 0.69314718056<span> ÷ --.03
t =</span><span><span><span> 23.1049060187
</span>
about 23 years
</span></span>
Answer:
$46
Step-by-step explanation:
Cost: 4p + 3c + 16
if p=3 and c=6 then,
4(3) + 3(6) +16
12+18+16
46 dollars spent
Divide 13 by 16. A fraction represents a division problem. 5/10 is 5 divided by 10 or 0.5 or 50%. Hope this helps
You should add them up both of the sides
Answer:
C.I = $251.2
Step-by-step explanation:
P = Principal amount = 1600
r = rate of annual interest = 6%
n = period / no. of years = 2.5 years
C.I = (P* (1+r^n))-P
C.I = (1600*(1+0.06)^2.5))-1600
C.I = (1600*(1.06^2.5))-1600
C.I = (1600*1.157)-1600
C.I = 1851.2-1600
C.I = 251.2
