Margin of error formula:
ME = z * (Sigma) / √ n
z = 1.96 for a 95 % confidence interval;
Sigma = 3 ( the population standard deviation )
n = 500
ME = 1.96 * 3 / √500 =
= 1.96 * 3 / 22.36 =
= 5.88 / 22.36 = 0.263
Answer:
The margin error for a 95% confidence interval is 0.263.
Yes you are correct good job
Putting it in simpler terms
the sequence is in multiples of 4 (2*4=8, 8*4=32, 32*4=128)
so 128*4=512, 512*4=2048, 2048*4=8192 & 8192*4=32768
2+8+32+128+512+2048+8192+32768=43690