One possible solution is
f(x) = x^4
g(x) = x-3
Since
f(x) = x^4
f(g(x)) = ( g(x) )^4
f(g(x)) = ( x-3 )^4
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Another possible solution could be
f(x) = x^2
g(x) = (x-3)^2
Because
f(x) = x^2
f(g(x)) = ( g(x) )^2
f(g(x)) = ( (x-3)^2 )^2
f(g(x)) = (x-3)^(2*2)
f(g(x)) = (x-3)^4
2 consecutive even integers : x and x + 2
4(x) + 3(x + 2) = 20
4x + 3x + 6 = 20
7x + 6 = 20
7x = 20 - 6
7x = 14
x = 14/7
x = 2
x + 2 = 2 + 2 = 4
so ur first number (x) = 2 and ur second number (x + 2) = 4
X= width
length= 3x-7
Area: (x)(3x-7)=40
= 3x^2-7x=40
= 3x^2-7x-40=0
Factorise the equation: (3x+8)(x-5)=0
x=-8/3 (reject because width cannot be negative) or x=5
so width is 5cm and length is 3(5)-7= 8cm !
Answer:
x = 6 units
Step-by-step explanation:
By geometric mean property:
Answer:
B. $24,000 for the rent and $18,000 for the insurance.
Step-by-step explanation:
Accrual method is a way of recording accounting transactions for revenue based on the time when they are earned and when the expenses are incurred.
Here, in the given scenario, $24,000 is accrued or $2000 per month is accrued.
The payment for insurance or rent spans for 2 time periods. That is six months this year and six months next year.
We know that insurance is a type of payment liability and accrues only when its paid.
So, he answer here will be option B.
