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Elenna [48]
2 years ago
10

What is the exponential expression for the numerical expression ​14⋅14⋅14⋅14​?

Mathematics
2 answers:
Bumek [7]2 years ago
5 0
Other person is correct it’s 14^4
olganol [36]2 years ago
4 0

Answer:

14^4

Step-by-step explanation:

I'm built different

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Three good friends are in the same algebra class. Their scores on a recent test are three consecutive integers whose sum is 252
vichka [17]

Answer:

83, 84, 85

Step-by-step explanation:

3 0
3 years ago
Activity 1.1 Simplify Me Simplify by removing perfect nth powers: 1. √20 2. √300 3. √128 3 4. √ 5 3 5. √50 3
LekaFEV [45]

Answer:

(a)\ \sqrt{20}=2\sqrt{5}

(b)\ \sqrt{300} = 10 \sqrt{3}

(c)\ \sqrt{128} = 8 \sqrt{2}

Step-by-step explanation:

Required

Simplify

(a)\ \sqrt{20}

Express 20 as 4 * 5

\sqrt{20}=\sqrt{4 * 5}

Split

\sqrt{20}=\sqrt{4} * \sqrt{5}

This gives:

\sqrt{20}=2 * \sqrt{5}

\sqrt{20}=2\sqrt{5}

(b)\ \sqrt{300

Express as 100 * 3

\sqrt{300} = \sqrt{100} * \sqrt{3}

This gives:

\sqrt{300} = 10 * \sqrt{3}

\sqrt{300} = 10 \sqrt{3}

(c)\ \sqrt{128}

Express as 64 * 2

\sqrt{128} = \sqrt{64*2}

Split

\sqrt{128} = \sqrt{64} * \sqrt{2}

\sqrt{128} = 8 * \sqrt{2}

\sqrt{128} = 8 \sqrt{2}

<em></em>

<em>Questions 4 and 5 are not clear</em>

<em>Follow the steps in 1 - 3 to solve 4 and 5</em>

7 0
2 years ago
Kathy starts with a number she adds 3 touring numbers then doubles the results finally she subtract 7 if she ended with nine wha
Ann [662]

she ends up getting 5

8 0
3 years ago
Solve with solution...no spam answers pls
Agata [3.3K]
<span>Let's analyze Hannah's work, step-by-step, to see if she made any mistakes. 

</span>In Step 1, Hannah wrote \dfrac{d}{dx} (-3+8x) <span> as the sum of two separate derivatives </span>\dfrac{d}{dx}(-3)+ \dfrac{d}{dx} (8x) <span>using the </span><span>sum rule.
</span>
This step is perfectly fine. 

In Step 2, \dfrac{d}{dx}(8x) was kept as it is, and \dfrac{d}{dx}(-3) was rewritten as 0 using the constant rule.Indeed, according to the constant rule, the derivative of a constant number is equal to zero.

This step is perfectly fine. 

In Step 3, \dfrac{d}{dx} (8x)  was rewritten as \dfrac{d}{dx}(8) \dfrac{d}{dx}(x) supposedly using the constant multiple rule.

The problem is that according to the constant multiple rule, \dfrac{d}{dx}(8x)&#10; should be rewritten as 8 \dfrac{d}{dx}(x) and not as \dfrac{d}{dx}(8)\dfrac{d}{dx}(x).  

<span>Therefore, Hannah made a mistake in this step.</span>
6 0
3 years ago
Read 2 more answers
Alfred made 20 goals in 3.5 minutes.what is alfreds unit rate per goal
Veseljchak [2.6K]
I belive the unit rate per goal is 5.7
5 0
3 years ago
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