What is the exponential expression for the numerical expression 14⋅14⋅14⋅14?

Mathematics

2 answers:

Bumek [7]3 years ago

5 0

Other person is correct it’s 14^4

olganol [36]3 years ago

4 0

Answer:

14^4

Step-by-step explanation:

I'm built different

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2 years ago

Segment addition postulate Find PQ

Readme [11.4K]

Answer:

PQ = 4

Step-by-step explanation:

As ; PQ=QR

PR = 8

PR= PQ+QR —> 8 = 2x —> x= 8/2 = 4

SO ; PQ = 4 , QR = 4

I hope I helped you^_^

8 0

3 years ago

Read 2 more answers

Situation:

Gala2k [10]

Answer:

5.5 days (nearest tenth)

Step-by-step explanation:

Given formula:

$\sf N=N_0e^{-kt}$

$\sf N_0$ = initial mass (at time t=0)
N = mass (at time t)
k = a positive constant
t = time (in days)

Given values:

$\sf N_0$ = 11 g
k = 0.125

Half-life: The time required for a quantity to reduce to half of its initial value.

To find the time it takes (in days) for the substance to reduce to half of its initial value, substitute the given values into the formula and set N to half of the initial mass, then solve for t:

$\begin{aligned}\sf N & = \sf N_0e^{-kt}\\\\\implies \sf \dfrac{11}{2} & = \sf 11e^{-0.125t}\\\\\sf \dfrac{1}{2} & = \sf e^{-0.125t}\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf \ln e^{-0.125t\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t \ln e\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t(1)\\\sf t & = \sf \dfrac{\ln \left(\dfrac{1}{2}\right)}{-0.125}\\\\\sf t & = \sf 5.545177444...\\\\\sf t & = \sf 5.5\:\:days\:\:(nearest\:tenth)\end{aligned}$