All categories

2 years ago

What does 0= -12 mean regarding the solution to the system?

Mathematics

2 answers:

Anuta_ua [19.1K]2 years ago

6 0

Answer:

There are no solutions to the system because the equations represent parallel lines.

Step-by-step explanation:

Lunna [17]2 years ago

6 0

Answer:

What does 0 = −12 mean regarding the solution to the system? There are no solutions to the system because the equations represent parallel lines.

You might be interested in

Please help me out Thank you!!

Roman55 [17]

Y=2x

2x3 = 6
2x5 = 10
Etc.

4 0

3 years ago

Read 2 more answers

Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8

Blababa [14]

$w(s,t)=f(u(s,t),v(s,t))$

From the given set of conditions, it's likely that you are asked to find the values of $\dfrac{\partial w}{\partial s}$ and $\dfrac{\partial w}{\partial t}$ at the point $(s,t)=(1,0)$ .

By the chain rule, the partial derivative with respect to $s$ is

$\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}$

and so at the point $(1,0)$ , we have

$\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}$
$\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21$

Similarly, the partial derivative with respect to $t$ would be found via

$\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}$
$\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5$

6 0

3 years ago

Will give brainliest

serious [3.7K]

Answer:

[2(x+10)]°+(3x-30)°=180°[vertically opposite angle]

2x+20+3x-30=180°

5x-10=180°

5x=180-10

5x=170

x=170/5

x=34

6 0

2 years ago

Solve the system using the substitution method: 3x + 5y = -10 X - 5y =-10

inn [45]

Answer:

Point Form:

(−5,1)

Equation Form:

x=−5, y=1

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

1. x=5y−10

2. 20y−30=−10

3. y=1

4. x=−5

4 0

3 years ago

3(12-8)/2*5-4 simplify or evaluate the following expressions

vekshin1

Answer:

Step-by-step explanation:

12-8=4

3(4)=12

12/2=6

6*5=30

30-4

4 0

2 years ago