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2 years ago

10

What is the critical value t* which satisfies the condition that the t distribution with 14 degrees of freedom has probability 0

.35 to the right of t*

1 answer:

Oduvanchick [21]2 years ago

8 0

Answer:

$t_{0.35,14}= 0.3933306$

Step-by-step explanation:

From the question we are told that:

Degree of freedom $df=14$

Significance Level $\alpha=0.35$

Generally the expression for critical value t is mathematically given by

$t_{\alpha,df}$

$t_{0.35,14}$

Therefore From Students T Value Table

$t_{0.35,14}= 0.3933306$

$T-Value (right-tailed): 0.3933306$

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12. The perimeter of a rectangle is 50 feet. The width is 5 less than the

Vlad [161]

Step-by-step explanation:

Length = x

Width = (x-5)

Perimeter = 2 lengths + 2 widths

50 ft = x + x + (x-5) + (x-5)

50 ft = 4x - 10

60 ft = 4x

15 ft = x

length = x = 15 ft

width = (x-5) = (15 -5) = 10 ft

dimensions = length × width

= 15 ft × 10 ft

if you wanna check,

50 ft = x + x + (x-5) + (x-5)

50 ft = 15 + 15 + (15-5) + (15-5)

50 ft = 30 +(10+10)

50 ft = 30 + 20

50 ft = 50

7 0

3 years ago

Kersha has two jobs. During the day she works as an office clerk, and in the evening she works as a cashier. Her office job pays

VLD [36.1K]

Let x = hours worked as a clerk ($12 per hour).
Let y = hours worked as a cashier ($8.25 per hour).

She worked 55 hours, therefore
x + y = 55 (1)

She earned $585, therefore
12x + 8.25y = 585 (2)

From (1), obtain
y = 55 - x (3)

Substitute (3) into (2).
12x + 8.25(55 - x) = 585
12x + 453.75 - 8.25x = 585
3.75x = 131.25
x = 35
y = 55 - x = 55 - 35 = 20

Answer: a) Office clerk: 35 hours; cashier: 20 hours.

7 0

3 years ago

Can you help me with this

Bess [88]

Answer:

3 and 4

Step-by-step explanation:

7 0

2 years ago

Find the value of x/y if (3/5)^4*(15/10)^4=x/y^4

scoray [572]

Answer:

9/10

Step-by-step explanation:

3^4/5^4 × 15^4/10^4=x^4/y^4

81/625 × 50625/10000= x^4/y^4

multiply

4100625/6250000=x^4/y^4

break it down by dividing it by 5

820125/1250000

divide by 5

164025/250000

divide by 5

32805/50000

divide by 5

6561/10000 = x^4/y^4

4√6561/4√10000=x/y

9/10= x/y

7 0

2 years ago

AnnZ [28]

Answer:

The average rate of change of $f(x) = x^2 +6x+13$ is 12

The average rate of change of $f(x) =- x^2 +6x+13$ is 10

Step-by-step explanation:

The average rate of change of f(x) over an interval between 2 points (a ,f(a)) and (b ,f(b)) is the slope of the secant line connecting the 2 points.

We can calculate the average rate of change between the 2 points by

$\frac{f(b) - f(a)}{b -a}$ -------------------(1)

(1) The average rate of change of the function $f(x) = x^2 +6x+13$ over the interval 1 ≤ x ≤ 5

f(a) = f(1)

$f(1) = (1)^2 +6(1) + 13$

f(1) =1+6+13

f(a) = 20---------------------(2)

f(b) = f(5)

$f(5) = (5)^2 +6(5)+13$

f(5) = 25 +30 +13

f(5) = 68-----------------------(3)

The average rate of change between (1 ,20) and (5 ,68 ) is

Substituting eq(2) and(3) in (1)

= $\frac{f(5) - f(1)}{5-1}$

= $\frac{68 -20}{5-1}$

= $\frac{48}{4}$

=12

This means that the average of all the slopes of lines tangent to the graph of f(x) between (1 ,20) and (5 ,68 ) is 12

(2) The average rate of change of the function $f(x) = -x^2 +6x+13$ over the interval -1 ≤ x ≤ 5

f(a) = f(-1)

$f(1) = (-1)^2 +6(-1) + 13$

f(1) =1-6+13

f(1) = 8---------------------(4)

f(b) = f(5)

$f(5) = (5)^2 +6(5)+13$

f(5) = 25 +30 +13

f(5) = 68-----------------------(5)

The average rate of change between (-1 ,8) and (5 ,68 ) is

Equation (1) becomes

$\frac{f(5) - f(-1)}{5-(-1)}$

On substituting the values

= $\frac{68 - 8}{5-(-1)}$

= $\frac{60}{5+1}$

= $\frac{60}{6}$

= 10

This means that the average of all the slopes of lines tangent to the graph of f(x) between (-1 ,8) and (5 ,68 ) is 10

4 0

3 years ago