Answer:
Try abc ÷ 2
Step-by-step explanation:
F Class = a
S Class = b
T Class = c
a + b + c = abc
Two buses = 2
abc ÷ 2
Step-by-step explanation:
Left hand side:
4 [sin⁶ θ + cos⁶ θ]
Rearrange:
4 [(sin² θ)³ + (cos² θ)³]
Factor the sum of cubes:
4 [(sin² θ + cos² θ) (sin⁴ θ − sin² θ cos² θ + cos⁴ θ)]
Pythagorean identity:
4 [sin⁴ θ − sin² θ cos² θ + cos⁴ θ]
Complete the square:
4 [sin⁴ θ + 2 sin² θ cos² θ + cos⁴ θ − 3 sin² θ cos² θ]
4 [(sin² θ + cos² θ)² − 3 sin² θ cos² θ]
Pythagorean identity:
4 [1 − 3 sin² θ cos² θ]
Rearrange:
4 − 12 sin² θ cos² θ
4 − 3 (2 sin θ cos θ)²
Double angle formula:
4 − 3 (sin (2θ))²
4 − 3 sin² (2θ)
Finally, apply Pythagorean identity and simplify:
4 − 3 (1 − cos² (2θ))
4 − 3 + 3 cos² (2θ)
1 + 3 cos² (2θ)
Answer:Did you figure it out?
Step-by-step explanation:
Answer: Option C.
Step-by-step explanation:
A) The result of the substitution shown in Option A is obtained by solving for y from the first equation and substituting into the second equation:


Therefore, this is a result of a substitution in the given system.
B) The result of the substitution shown in Option B is obtained by solving for y from the second equation and substituting into the first equation:



Therefore, this is a result of a substitution in the given system.
C) The result of the substitution shown in Option C is not a result of a substitution in the given system, because if you solve for x from the second equation and substitute into the first one, you get:

Answer:
x = 110
Step-by-step explanation:
comment if you want explanation