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dimaraw [331]
3 years ago
5

Please help I’m confused math is hard!

Mathematics
1 answer:
Butoxors [25]3 years ago
3 0

Answer:

Step-by-step explanation:

basically, what they are asking you is to factor and then plug in the values (x=3; x=4) that they gave you.

first, you need to factor out the equation.

start with the original equation.

V=4x^3+10x^2+4x

factored form:

V= 2x(2x^2+5x+2)

next, you're going to want to plug in the values.

the answer asks for x=4, but you should do both.

v=2(3)(2(3)^2+5(3)+2)

do not forget to do the exponents before!

v=6(18+15+2)

v=6(35)

v=210 ft^2

that's the answer for if x was equal to 3.

V= 2x(2x^2+5x+2)

<em>don't forget to write the original equation first. </em>

V=2(4)(2(4)^2+5(4)+2)

<em>V=8(36+20+2)</em>

<h2><u><em>V=464 ft^2  </em></u></h2>

⬆is your answer! hope this helped!!

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Answer:

The probability that 3 sports cars are parked together is 0.0833.

Step-by-step explanation:

An attendant has to park 9 cars.

He can park all the 9 cars i, 9! = 362880 ways.

If the attendant park the cars such that all three sports car are parked next to each other, then the number of ways to do this is:

Consider the 3 sports cars as 1 unit.

Then there are total 7 parking spaces, _, _, _, _, _, _, <u>(SSS)</u>

The three sports cars can be parked together in 3! = 6 ways.

The remaining 6 cars can be parked in 6! = 720 ways.

Compute the probability that 3 sports cars are parked together as follows:

P(3\ sports\ cars\ together)=\frac{7\times6!\times3!}{9!}=\frac{7\times720\times6}{362880}=  0.0833

Thus, the probability that 3 sports cars are parked together is 0.0833.

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Step-by-step explanation:

P(E) =  

Let 'B' be the event of having twelve year old brother

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