Write four hundred seven trillion six million one hundred five thousand twenty eight in standard form

Mathematics

2 answers:

garri49 [273]3 years ago

7 0

407,600,105,028

Standard form is the basic form in numbers so basically you take the words and put them into numbers

Ratling [72]3 years ago

4 0

Standard form would be
.407600105028
Hope this helps

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Find the average value of f(x)=e2x over the interval [2, 4].

shusha [124]

<h2>Option B is the correct answer.</h2>

Step-by-step explanation:

We need to find average value of $e^{2x}$ in [2,4]

Area of $e^{2x}$ in [2,4] is given by

$\int_{2}^{4}e^{2x}dx=\frac{1}{2}\times \left [ e^{2x}\right ]^4_2\\\\\int_{2}^{4}e^{2x}dx=\frac{1}{2}\times(e^8-e^4)=1463.18$

Area of $e^{2x}$ in [2,4] = 1463.18

Difference = 4 - 2 = 2

Average value = Area of $e^{2x}$ in [2,4] ÷ Difference

Average value = 1463.18 ÷ 2

Average value = 731.59

Option B is the correct answer.

5 0

3 years ago

40% of students on a field trip love the museum. If there are 20 students on the field trip, how many love the museum??

MariettaO [177]

Since there are 20 students on the field trip. Then 20 is the 100% total. Thus, to find how many people love the museum, we can simply multiply the total number of people by the percentage of interest, namely 40%

20*0.4 = 8
So, 8 people love the museum.

5 0

3 years ago

Can someone help me with this?

Anna35 [415]

Answer:

Let 'a' be the first term, 'r' be the common ratio and 'n' be the number of terms

Series = 2+6+18.......= 2+2•3¹+ 2•3².......= 728

Now,

$Sum = \frac{a( {r}^{n} - 1) }{(r - 1)} \\$

So,

$\frac{a( {r}^{n} - 1)}{(r - 1)} = 728 \\ \frac{2( {3}^{n} - 1) }{(3 - 1)} = 728 \\ \frac{2( {3}^{n} - 1) }{2} = 728 \\ {3}^{n} - 1 = 728 \\ {3}^{n}=728+1\\ {3}^{n} = 729 \\ {3}^{n} = {3}^{6} \\ \boxed{ n = 6}$