For f(x)=1/x^2-3
Find
A) f(3)
B) f(2-h)
If f(x)=1/x^2-3, then f(3) = 1 / 3^2 - 3. The exponentiation here must be carried out first: f(3) = 1/9 - 3. Then f(3) = 1/9 - 27/9 = -26/9
If f(x)=1/x^2-3, then f(2-h) = 1 / [2-h]^2 - 3. This result may be left as is or expanded. In expanded form, we have:
1
f(2-h) = ------------------ - 3
4-4h +h^2
The picture in the attached figure
[surface area of the composite solid]=1*(4*6)+2*(4*4)+2*(4*6)+2*(4*√13/2)+2*(6*2√2/2)
[surface area of the composite solid]=24+32+48+4√13+12√2
[<span>surface area of the composite solid]=135.39 yd</span>²
the answer is135.39 yd²
Answer:
∠ACB = 28.5
Step-by-step explanation:
In triangle ABC,
angle CAB = x-3
angle ABC = 4X-3
It is also given that AB=CB
We know that if two sides of any triangle are equal then corresponding sides must also be equal.
Hence
angle ACB = angle CAB
angle ACB = x-3 {Given that angle CAB = x-3 }
We know that sum of all three angles of a triangle is 180 degree so let's add given angles
angle ACB + angle CAB + angle ABC = 180
(x-3) + (x-3) + (4x-3) = 180
x-3 + x-3 + 4x-3 = 180
6x-9 = 180
6x = 180+9
6x = 189
x = 189/9
x= 31.5
Now plug value of x into
angle ACB = x-3 = 31.5-3 = 28.5
Hence final answer is
∠ACB = 28.5
1)inside the triangule is 180º .There are 3 angules, one with 120º, theta and
angle ACB, lets call it x.
x + theta + 120 = 180
x + theta= 180-120
x + theta= 60
x= 60- theta
angle ACB= 60- theta
Answer: 384 in
Step-by-step explanation: 12 in*10 in=384 in
