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Eddi Din [679]
3 years ago
13

Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula?

Quadratic formula: x = -b
Mathematics
1 answer:
ZanzabumX [31]3 years ago
3 0

Answer:

shows correct substitution of the values a, b, and c  from the given quadratic equation    into quadratic formula.

Step-by-step explanation:

Given: The quadratic equation

We have to show the correct substitution of the values a, b, and c from the given quadratic equation    into quadratic formula.

The standard form of quadratic equation is  then the solution of quadratic equation using quadratic formula is given as

Consider the given  quadratic equation

Comparing with general  quadratic equation, we have

a = -3 , b = -2 , c = 6

Substitute in quadratic formula, we get,

Simplify, we have,

Thus,  and x_{2}=\frac{2-\sqrt{76} }{-6}

Simplify, we get,

Thus,  shows correct substitution of the values a, b, and c  from the given quadratic equation    into quadratic formula.

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3 years ago
3a² + 11a – 42<br><br>this is factoring in algebra 2 (high school) <br>​
N76 [4]

To factor,

<h2>[[[</h2>

1) First multiply coefficient of a² and constant no,

That is,

3×(-42)=-126

Since the<u> resultant no is negative</u>, you should find two such factors of 126 <u>which</u> <u>will give us the coefficient of a (=11)</u> on subracting those factors.

2) Find the factor

126=2×3×3×7

=18×7

18 and 17 are factors of 126

Also,18-7 =11.

So they are required factors for factoring,

<h2>]]]</h2>

Once you have understood above steps you can solve on your own. All you need to do is split 11 into factors ,take common terms and you will get answer.

<u>Answer:</u>

3a²+11a-42

=3a²+(18-7)a -42

=3a²+18a-7a-42

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3 years ago
Find the range of the following piecewise function.
Anna11 [10]

Given:

The piecewise function is

f(x)=\begin{cases}x+4 & \text{ if } -4\leq x

To find:

The range of given piecewise function.

Solution:

Range is the set of output values.

Both functions f(x)=x+4 and f(x)=2x-1 as linear functions.

Starting value of f(x)=x+4 is at x=-4 and end value is at x=3.

Starting value: f(-4)=-4+4=0

End value: f(3)=3+4=7

Starting value of f(x)=2x-1 is at x=3 and end value is at x=6.

Starting value: f(3)=2(3)-1=5

End value: f(6)=2(6)-1=11

Least range value is 0 at x=-4 and 0 is included in the range because -4 is included in the domain.

Largest range value is 11 at x=6 and 11 is not included in the range because 6 is not included in the domain.

So, the range of the given piecewise function is [0,11).

Therefore, the correct option is A.

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