1. We want to add all alike terms and follow GEMDAS as well. Addition first 2x+3x=5x ,then -x(which is equal to -1x) + 10x = 9x. Now we add 5x + 9x = 14x.
Right now the equation looks like:
14x + 14 = -42

2. Now we process the equation,
Subtract 14 from the left side, but what u do to one side u do to the other so now the equation looks like:
14x = -56

3. Now we are almost finished last step.
14x changes to x and we divide -56 by 14 which equals -4. The answer is
X = -4

Ps. I spent way too long writing this answer

6 0

3 years ago

Please help me it’s due today please help me please please people help me please please

SCORPION-xisa [38]

Answer:

a) 0≠ -10

b) x= -3

c)y= 0

Step-by-step explanation:

a) 3-4x=-7-4x

$3-4x=-7-4x\\Adding \ 4x \ on \ both \ sides\\3-4x+4x=-7-4x+4x\\3-0=-7\\Adding \ -3\\3-0-3=-7-3\\0\neq -10$

So, this equation has no solution as both sides are not equal.

b) $15-2x=-7x$

Solving:

$15-2x=-7x\\Adding \ 2x \ on \ both \ sides\\15-2x+2x=-7x+2x\\15=-5x\\Divide \ both \ sides \ by -5\\x=-3$

So, this equation has one solution

c) 7(y-3)=6y-21

Solving:

$7(y-3)=6y-21\\7y-21=6y-21\\Adding \ -6y \ on \ both \ sides\\7y-21-6y=6y-21-6y\\y=-21+21\\y=0$

So, this equation has one solution.

1. Write equation with no solution. 3-4x=-7-4x (check solution of a)

2. Write equation with one solution. 7(y-3)=6y-21 (check solution of c)

3. Write equation with infinite solution. 2x + 3 = x + x + 3

solving:

2x+3=2x+3

2x-2x+3=3

3=3

When both sides are equal, the equation has infinite solutions.

6 0

3 years ago

Suppose that the functions s and t are defined for all real numbers x as follows.

Svetllana [295]

$s(x)=2x+4;\ D_s=\mathbb{R}\\\\t(x)=5x;\ D_t=\mathbb{R}\\\\D_s=D_t\\\\(s+t)(x)=s(x)+t(x)=2x+4+5x=7x+4\\\\(s-t)(x)=s(x)-t(x)=2x+4-5x=-3x+4\\\\(s\times t)(x)=(2x+4)\times5x=10x^2+20x$

8 0

3 years ago

Solve 3[-x + (2 x + 1)] = x - 1.

torisob [31]

Step-by-step explanation:

3(-x+2x+1)=x-1

3(x+1)=x-1

3x+3=x-1

3x-x=-1-3

2x=-4

x=-2

3 0

3 years ago

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