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Anon25 [30]
2 years ago
9

A store is selling a bicycle for $245.00. The store marks bicycles up by 40%. What is the original price of the bicycle?

Mathematics
1 answer:
Alex_Xolod [135]2 years ago
6 0

Answer:

147

Step-by-step explanation:

if you multiply by .40 then subtract that from 245 you get 147

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Step-by-step explanation:

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Fill in the missing number to complete the linear equation that gives the rule for this table.
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Determine if the equations are parallel, perpendicular, or neither.
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To easily find the slope from standard form (Ax + By = C) use -A/B

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Find the domain of the Bessel function of order 0 defined by [infinity]J0(x) = Σ (−1)^nx^2n/ 2^2n(n!)^2 n = 0
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Answer:

Following are the given series for all x:

Step-by-step explanation:

Given equation:

\bold{J_0(x)=\sum_{n=0}^{\infty}\frac{((-1)^{n}(x^{2n}))}{(2^{2n})(n!)^2}}\\

Let   the value a so, the value of a_n  and the value of a_(n+1)is:

\to  a_n=\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}

\to a_{(n+1)}=\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}

To calculates its series we divide the above value:

\left | \frac{a_(n+1)}{a_n}\right |= \frac{\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}}{\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}}\\\\

           = \left | \frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2} \cdot \frac {2^{2n}(n!)^2}{(-1)^2n x^{2n}} \right |

           = \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)!^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |

           = \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\= \left | \frac{x^{2n}\cdot x^2}{2^{2n} \cdot 2^2(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\

           = \frac{x^2}{2^2(n+1)^2}\longrightarrow 0   for all x

The final value of the converges series for all x.

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