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Alona [7]
3 years ago
6

Select the linear equation represented in the graph

Mathematics
2 answers:
Goshia [24]3 years ago
8 0

Answer:

theres no graph?

Step-by-step explanation:

zubka84 [21]3 years ago
6 0

Answer:

what's the graph because you have no image

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Which expression shows 36 as a product of prime factors?
Lapatulllka [165]

Answer:

This is ur answer

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NO LINKS!!!<br><br>14. Consider the table​
iVinArrow [24]

Answer:

(a) rate of change = 8

(b) Function: y = 8x

(c) Domain: 0 ≤ x ≤ 2

    Range: 0 ≤ y ≤ 16

Explanation:

Looks like a inverse variation sequence.

Inverse Variation formula: y = k(x)

Take two points: (1, 8), (2, 16)

Find the value of k which is constant also considered as <u>rate of change</u>.

<u>Insert values</u>:

  • 8 = k(1)
  • k = 8

===========

  • 16 = k(2)
  • k = 8

Equation: y = 8x

Domain lies in the x axis, Range lies in the y axis.

  • Here domain: 0 ≤ x ≤ 2
  • Here range: 0 ≤ y ≤ 16
5 0
2 years ago
Read 2 more answers
I need to find the derivative. I’m not very good at this so I am answer asap would be sosososo helpful
Bingel [31]

Answer:

See below.

Step-by-step explanation:

First, notice that this is a composition of functions. For instance, let's let f(x)=\sqrt{x} and g(x)=7x^2+4x+1. Then, the given equation is essentially f(g(x))=\sqrt{7x^2+4x+1}. Thus, we can use the chain rule.

Recall the chain rule: \frac{d}{dx}[f(g(x))]=f'(g(x))\cdot g'(x). So, let's find the derivative of each function:

f(x)=\sqrt{x}=x^\frac{1}{2}

We can use the Power Rule here:

f'(x)=(x^\frac{1}{2})'=\frac{1}{2}(x^{-\frac{1}{2}  })=\frac{1}{2\sqrt{x}}

Now:

g(x)=7x^2+4x+1

Again, use the Power Rule and Sum Rule

g'(x)=(7x^2+4x+1)'=(7x^2)'+(4x)'+(1)'=14x+4

Now, we can put them together:

y'=f'(g(x))\cdot g'(x)=\frac{1}{2\sqrt{g(x)}} \cdot (14x+4)

y'=\frac{14x+4}{2\sqrt{7x^2+4x+1} } =\frac{7x+2}{\sqrt{7x^2+4x+1} }

5 0
3 years ago
Y = f(x) = 25x<br><br> Find f(x) when x= 1/2
Ray Of Light [21]

Answer:

12.5

Step-by-step explanation:

f of x just means y, so you're just finding y when x = 1/2

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