Help!! I spent hours trying to figure this out!! Answer was incorrect. And it has to be written in equation or fraction format.
No decimals.
Here’s my work:
Using a substitution
u = 4 * x^(-2)
du = -8 * x^(-3) * dx
(-1/8) * du = x^(-3) * dx
Now I have:
e^(4x^(-2)) * dx / x^3 =>
e^(u) * (-1/8) * du
Integrate
(-1/8) * e^(u) + C =>
(-1/8) * e^(4x^(-2)) + C
From 4 to 6
(-1/8) * e^(4 * 6^(-2)) + (1/8) * e^(4 * 4^(-2)) =>
(1/8) * (e^(4/16) - e^(4/36)) =>
(1/8) * (e^(1/4) - e^(1/9))
Here’s my work:
Using a substitution
u = 4 * x^(-2)
du = -8 * x^(-3) * dx
(-1/8) * du = x^(-3) * dx
Now I have:
e^(4x^(-2)) * dx / x^3 =>
e^(u) * (-1/8) * du
Integrate
(-1/8) * e^(u) + C =>
(-1/8) * e^(4x^(-2)) + C
From 4 to 6
(-1/8) * e^(4 * 6^(-2)) + (1/8) * e^(4 * 4^(-2)) =>
(1/8) * (e^(4/16) - e^(4/36)) =>
(1/8) * (e^(1/4) - e^(1/9))
1 answer:
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Answer:
a) x =3 and x=5
c) x =-1 and
i) x =0 and
Step-by-step explanation:
a)
Given that the quadratic equation
x² - 8x +15 =0
The factors of 15 = 5 × 3
x² - 5x -3x +15 =0
x(x -5) -3(x-5) =0
(x-3)(x-5) =0
x =3 and x=5
c)
3 x² + 10 x +7 =0
⇒ 3x² + 3x + 7x +7 =0
⇒ 3x (x +1) +7(x+1) =0
⇒ (x+1) ( 3 x +7) =0
⇒ x =-1 and
i)
2 x ² + 9 x =0
⇒ x( 2 x + 9) =0
⇒ x =0 and 2 x = -9
⇒ x =0 and
Answer:
The dimensions that minimize the surface are:
Wide: 1.65 yd
Long: 3.30 yd
Height: 2.20 yd
Step-by-step explanation:
We have a rectangular base, that its twice as long as it is wide.
It must hold 12 yd^3 of debris.
We have to minimize the surface area, subjet to the restriction of volume (12 yd^3).
The surface is equal to:
The volume restriction is:
If we replace h in the surface equation, we have:
To optimize, we derive and equal to zero:
Then, the height h is:
The dimensions that minimize the surface are:
Wide: 1.65 yd
Long: 3.30 yd
Height: 2.20 yd
