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alexira [117]
4 years ago
15

Suppose a triangle has sides a, b, and c, and let theta be opposite the side of length a. If cos theta < 0, what must be true

?
Mathematics
1 answer:
katrin2010 [14]4 years ago
6 0
If \cos \theta\ \textless \ 0, then angle \theta is obtuse and triangle with sides a, b, c is obtuse triangle.
In an arbitrary triangle can be only one obtuse angle, and the side which lies opposite to the largest angle is the largest. Then since <span>angle \theta is opposite the side of length a</span>  you can conclude that a>c and a>b.



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notsponge [240]

Answer:

30

Step-by-step explanation:

30 + 30 = 60

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30 * 30 = 900

I hope I helped!

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Step-by-step explanation:

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Ksivusya [100]

Answer:

125\ ft

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the right triangle ABC find the length side BC

we know that

tan(62\°)=\frac{124}{BC}

BC=\frac{124}{tan(62\°)}

step 2

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we know that

tan(33\°)=\frac{124}{BD}

BD=\frac{124}{tan(33\°)}

step 3

we know that

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CD=BD-BC

substitute the values  

CD=\frac{124}{tan(33\°)}-\frac{124}{tan(62\°)}=125\ ft

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Answer:

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