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alexira [117]
3 years ago
15

Suppose a triangle has sides a, b, and c, and let theta be opposite the side of length a. If cos theta < 0, what must be true

?
Mathematics
1 answer:
katrin2010 [14]3 years ago
6 0
If \cos \theta\ \textless \ 0, then angle \theta is obtuse and triangle with sides a, b, c is obtuse triangle.
In an arbitrary triangle can be only one obtuse angle, and the side which lies opposite to the largest angle is the largest. Then since <span>angle \theta is opposite the side of length a</span>  you can conclude that a>c and a>b.



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Write an expression to describe the situation. "Your cell phone costs $50 a month plus $0.25 for each text message (t). Do not i
sveticcg [70]

The expression is 50 + 0.25t.

<h3>How to compute the value?</h3>

It should be noted that from the information, the cell phone costs $50 a month plus $0.25 for each text message (t).

The expression will be:

= 50 + 0.25(t)

= 50 + 0.25t

Therefore, the expression is 50 + 0.25t.

Learn more about expressions on:

brainly.com/question/723406

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8 0
1 year ago
Look at this set of ordered pairs:
jeka57 [31]

Answer:

  • No

Step-by-step explanation:

<u>Given ordered pairs:</u>

  • (3, -13)
  • (3, 2)
  • (18,-5)

There is a repeat of domains (3) with different range (-13 and 2) but the function can't have repeat domains so it is not a function

4 0
3 years ago
Read 2 more answers
Ví dụ 1.5. Một người đi mua hàng 3 lần. Xác suất lần đầu mua được hàng tốt là 0,7.
vodka [1.7K]

Answer:

a) 0.50575,

b) 0.042

Step-by-step explanation:

Example 1.5. A person goes shopping 3 times. The probability of buying a good product for the first time is 0.7.

If the first time you can buy good products, the next time you can buy good products is 0.85;  (I interpret this as, if you buy a good product, then the next time you buy a good product is 0.85).

And if the last time I bought a bad product, the next time I bought a good one is  0.6. Calculate the probability that:

a) All three times the person bought good goods.

P(Good on 1st shopping event AND Good on 2nd shopping event AND Good on 3rd shopping event) =

P(Good on 1st shopping event) *P(Good on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st and 2nd shopping events yield Good) =

(0.7)(0.85)(0.85) =

0.50575      

b) Only the second time that person buys a bad product.

P(Good on 1st shopping event AND Bad on 2nd shopping event AND Good on 3rd shopping event) =

P(Good on 1st shopping event) *P(Bad on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st is Good and 2nd is Bad shopping events) =

(0.7)(1-0.85)(1-0.6) =

(0.7)(0.15)(0.4) =

0.042

5 0
3 years ago
This is very important!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
SpyIntel [72]

Answer:

Step-by-step explanation:

5 0
3 years ago
Which property is used in the problem below?<br><br> 2(x+4)=2x+8
frutty [35]

Answer:

You would use the distributive property.

Step-by-step explanation:

2(x+4) = 2x+8

2x+8x = 2x+8

10x = 2x+8

10x - 2x = 2x-2x+8

8x = 8

8x/8 = 8/8

x = 1

7 0
2 years ago
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