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Kaylis [27]
3 years ago
11

What are the dimensions of the matrix?

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
6 0

For this case we have that by definition, the dimension of a matrix is given by:

<em>The number of rows by the number of columns </em>

It is observed that we have a column that consists of three rows.

\left[\begin{array}{c}6&\\2&\\8&\end{array}\right]

Thus, the dimension of the matrix is 3 * 1

Answer:

3 * 1

Option A

denis-greek [22]3 years ago
3 0

Answer: 3 x 1

There are 3 rows and 1 column. We write the number of rows first. The rows are laid out horizontally while the columns are vertical. We say this is a "3 by 1 matrix".

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Eric sells shirts. It costs him $100 to buy all the shirts and $10, total, to print designs on them. Eric sells each shirt for $
4vir4ik [10]
4 is a coefficient and X and Y are variables so the -110 is the constant so there for the answer is D
8 0
3 years ago
Find the equation of a line passing through points (-7, -10) , (-5, -20)
LuckyWell [14K]

You want to find the equation for a line that passes through the two points:

                          (-7,-10) and (-5,-20).

First of all, remember what the equation of a line is:

                                y = mx+b

here, m is the slope, b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through.

Consider (-7,-10) as point #1, so the x and y numbers given will be called x1 and y1. Or, x1=-7 and y1=-10.

Consider (-5,-20), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-5 and y2=-20.

Now, just plug the numbers into the formula for m above, like this:

                       m= (-20 - -10)/(-5 - -7)

                                m= -10/2

                                   m=-5

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

                                     y=-5x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-7,-10). When x of the line is -7, y of the line must be -10.

(-5,-20). When x of the line is -5, y of the line must be -20.

Because  line passes through each one of these two points, right?

Now, look at our line's equation so far: y=-5x+b. b is what we want, the -5 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specifically passes through the two points (-7,-10) and (-5,-20).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.


You can use either (x,y) point you want.The answer will be the same:

(-7,-10). y=mx+b or -10=-5 × -7+b, or solving for b: b=-10-(-5)(-7). b=-45.

(-5,-20). y=mx+b or -20=-5 × -5+b, or solving for b: b=-20-(-5)(-5). b=-45.

See! In both cases we got the same value for b. And this completes our problem.

The equation of the line that passes through the points (-7,-10) and (-5,-20) is y=-5x-45.

                                 


8 0
3 years ago
[HELP ASAP 50 POINTS] 17, 18, 19, 20
Charra [1.4K]

17) f(x) = 16/(13-x).

In order to find domain, we need to set denominator expression equal to 0 and solve for x.

And that would be excluded value of domain.

13-x =0

Adding x on both sides, we get

13-x +x = x.

13=x.

Therefore, domain is All real numbers except 13.



18).f(x) = (x-4)(x+9)/(x^2-1).

In order to find the vertical asymptote, set denominator equal to 0 and solve for x.

x^2 -1 = 0

x^2 -1^2 = 0.

Factoring out

(x-1)(x+1) =0.

x-1=0 and x+1 =0.

x=1 and x=-1.

Therefore, Vertical asymptote would be

x=1 and x=-1

19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)

We have degrees of numberator and denominator are same.

Therefore, Horizontal asymptote is the fraction of leading coefficents.

That is 7/2.


20) f(x)=(x^2+3x-2)/(x-2).

The degree of numerator is 2 and degree of denominator is 1.

2>1.

Degree of numerator >  degree of denominator .

Therefore, there would no any Horizontal asymptote.

6 0
3 years ago
A cheetah ran 300 feet in 2.92 seconds. What was the cheetah’s average speed in miles per hour? Show your work.
alexdok [17]

Answer:

about 70.0 mph

Step-by-step explanation:

speed = distance/time

(300 ft)/(2.92 s)·(1 mi)/(5280 ft)·(3600 s)/(1 h) = (300·3600/(2.92·5280)) mi/h

≈ 70.0498 mi/h

8 0
3 years ago
Find the gradient of the line segment between the points N(-1,2) and M(-6,3)​
siniylev [52]

Answer:

1/5

Step-by-step explanation:

Gradient is another word for slope. To find the gradient, we have to use a formula.

8 0
3 years ago
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