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Fiesta28 [93]
2 years ago
14

PLZ HURRY IT'S URGENT!!! Find the volume of the prism.

Mathematics
1 answer:
Mashutka [201]2 years ago
7 0

Answer:

V = 210 cm³

Step-by-step explanation:

The volume (V) of a cube is calculated as

V = Ah ( A is the area of the base and h is the height )

Here A = 5 × 6 = 30 cm² and h = 7 cm , then

V = 30 × 7 = 210 cm³

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raj and his sister zia are both at secondary school. Raj is three years older than zia. the sum of the squares of their ages is
steposvetlana [31]

Let's assume

Raj's age is x years

Zia's age is y years

we are given

Raj is three years older than zia

so, we get

x=y+3

now, we can solve for y

y=x-3

the sum of the squares of their ages is 369

so, we get

x^2+y^2=369

now, we can plug back y

x^2+(x-3)^2=369

now, we can solve for x

2x^2-6x+9=369

2x^2-6x-360=0

x^2-3x-180=0

(x+12)(x-15)=0

x=-12 , x=15

Since, age can not be negative

so, we will only consider positive

x=15

now, we can find y-value

y=15-3

y=12

So,

Raj's age is 15 years

Zia's age is 12 years...........Answer

8 0
3 years ago
Jerri was using a recipe for a large cake that required one-fourth of a tablespoon of cinnamon. Instead of making one large cake
Sergeeva-Olga [200]

Im pretty sure you would put 1/12 tablespoon of cinnamon in the cakes individually. You would divide 1/4 by 3. It's pretty simple. If that's not the answer I apologize dearly!

8 0
3 years ago
Read 2 more answers
The sum of three consecutive integers is 267. What is the largest integer?
Stella [2.4K]

Answer:

let integers be x,2x, 3x respectively

x+2x+3x= 267

6x= 267

x=267/6= 44.5

2x= 44.5*2= 89

3x= 44.5*3= 133.5

largest integer = 133.5

hope it helps

plz mark as brainliest

5 0
3 years ago
Phil received a prize of xxx dollars from a poker tournament. The tournament cost him 100100100 dollars to enter.
nikitadnepr [17]

Answer:

$(x-100)

Step-by-step explanation:

  • Phil entered the poker tournament with $100.
  • He received a price of $x.

His net winnings from the tournament will be the price minus the entry fee.

Therefore:

Phil's net winnings=$(x-100)

8 0
3 years ago
find the centre and radius of the following Cycles 9 x square + 9 y square +27 x + 12 y + 19 equals 0​
Citrus2011 [14]

Answer:

Radius: r =\frac{\sqrt {21}}{6}

Center = (-\frac{3}{2}, -\frac{2}{3})

Step-by-step explanation:

Given

9x^2 + 9y^2 + 27x + 12y + 19 = 0

Solving (a): The radius of the circle

First, we express the equation as:

(x - h)^2 + (y - k)^2 = r^2

Where

r = radius

(h,k) =center

So, we have:

9x^2 + 9y^2 + 27x + 12y + 19 = 0

Divide through by 9

x^2 + y^2 + 3x + \frac{12}{9}y + \frac{19}{9} = 0

Rewrite as:

x^2  + 3x + y^2+ \frac{12}{9}y =- \frac{19}{9}

Group the expression into 2

[x^2  + 3x] + [y^2+ \frac{12}{9}y] =- \frac{19}{9}

[x^2  + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}

Next, we complete the square on each group.

For [x^2  + 3x]

1: Divide the coefficient\ of\ x\ by\ 2

2: Take the square\ of\ the\ division

3: Add this square\ to\ both\ sides\ of\ the\ equation.

So, we have:

[x^2  + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}

[x^2  + 3x + (\frac{3}{2})^2] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2

Factorize

[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2

Apply the same to y

[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y +(\frac{4}{6})^2 ] =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ \frac{9}{4} +\frac{16}{36}

Add the fractions

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{-19 * 4 + 9 * 9 + 16 * 1}{36}

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{21}{36}

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{7}{12}

[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}

Recall that:

(x - h)^2 + (y - k)^2 = r^2

By comparison:

r^2 =\frac{7}{12}

Take square roots of both sides

r =\sqrt{\frac{7}{12}}

Split

r =\frac{\sqrt 7}{\sqrt 12}

Rationalize

r =\frac{\sqrt 7*\sqrt 12}{\sqrt 12*\sqrt 12}

r =\frac{\sqrt {84}}{12}

r =\frac{\sqrt {4*21}}{12}

r =\frac{2\sqrt {21}}{12}

r =\frac{\sqrt {21}}{6}

Solving (b): The center

Recall that:

(x - h)^2 + (y - k)^2 = r^2

Where

r = radius

(h,k) =center

From:

[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}

-h = \frac{3}{2} and -k = \frac{2}{3}

Solve for h and k

h = -\frac{3}{2} and k = -\frac{2}{3}

Hence, the center is:

Center = (-\frac{3}{2}, -\frac{2}{3})

6 0
2 years ago
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