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Natali [406]
3 years ago
15

9 people shared 6 subs equally how much each person get

Mathematics
1 answer:
bogdanovich [222]3 years ago
5 0

.67

Step-by-step explanation6 divided by 9

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Multiply. Enter the product in simplest form.<br> uIN<br> =<br> 9/10 multiplied 2/5
natali 33 [55]

Answer:

When multiplying fractions, multiply the top number by the top number, and the bottom number by the bottom number.

So we have: (9x2)/(10x5).

This simplifies to: 18/50, or 9/25.

Let me know if this helps!

5 0
3 years ago
The probability of waiting 4 minutes or longer for checkout at a particular supermarket counter is 0.1. On a given day, a man an
Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

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3 0
3 years ago
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
Find the area of the figure.( sides meet at right angles.)picture below
Tema [17]

You can divide the figure as follows:

  • A vertical rectangle, 5 meters tall and 2 meters wide, on the top right.
  • A horizontal rectangle, 2 meters tall and 5 meters wide, on the bottom left
  • A 2x2 meters square on the bottom right, where the two rectangles meet.

The area of the rectangles is 5x2=10 meters squared, while the area of the square is 2x2=4 meters squared.

So, the total area is 10+4=14 meters squared.

5 0
3 years ago
Calculate the length CD. <br>I need to understand how to do it, can someone help me please? ​
kolbaska11 [484]

Answer:

77.6m (3 s.f.)

Step-by-step explanation:

Please see the attached pictures for full solution.

8 0
3 years ago
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