Supposse that the distance from the point to the point is equal to the distance from to the point . Then, by the formula of the distnace we must have
cancel the square root and the 's, and then expand the parenthesis to obtain
then, simplifying we obtain
therfore we must have
this means that the points satisfying the propertie must have first component equal to 5. So we can give a lot of examples of such points: . The set of this points give us a straight line and the points (3,0) and (7,0) are symmetric with respect to this line.
Answer:it turned out I was not gay after all
Step-by-step explanation:I was really into girls
The equation of the parabola in the vertex form is y = (x - 3 - 5 with ( 3, -5) is the vertex of the parabola and 1 is the multiplier
In the above question, A parabolic equation is given as follows:
Y = x^2 - 6x + 4
The equation of the parabola in the vertex form is :
y = a (x - h + k
Where a is a multiplier in the equation and (h,k) are the coordinates of the vertex
So, in order to obtain this form, we will use the method of completing square :
Y = x^2 - 6x + 4
y = - 6x + (9 -9) + 4
y = (x - 3 + ( -9 + 4)
y = (x - 3 - 5
where, ( 3, -5) is the vertex of the parabola and 1 is the multiplier
Hence, The equation of the parabola in the vertex form is y = (x - 3 - 5 with ( 3, -5) is the vertex of the parabola and 1 is the multiplier
To learn more about, parabola, here
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-5 ≤ 3m + 1 < 4
- 1 - 1 - 1
-6 ≤ 3m < 3
3 3 3
-2 ≤ m < 1
Solution Set: {m|-2 ≤ m < 1}, {m|m ≥ -2 and m < 1}, [-2, 1)
The answer is A.
Answer:
thats way to much
Step-by-step explanation:
OK