Answer:
(a) There are outliers
(b)
and 
Step-by-step explanation:
Given







Solving (a): Check for outliers
This is calculated using:
--- lower bound of outlier
--- upper bound of outlier
Where

So, we have:


The lower bound of outlier becomes




The upper bound of outlier becomes




So, we have:
--- the range without outlier
Given that:
--- This represents the lowest data
--- This represents the highest data
-24 and 64 are out of range of
.
Hence, there are outliers
Solving (b): The outliers
The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)
So, the outliers are:
and 
Answer:
<h2>it is 6 because it's hard to explain but all I know it's 6</h2>
Answer: 18.09yd
Step-by-step explanation:
A=πr^2
A= 3.14*2.4^2
A= 18.09yd
I hope you want to simplify this expression.
To simplify the given expression we can use the order of operation.
So, first step is to operate multiplication. Therefore,
400 x 34 = 13600
Hence,
400x34+23444444444-23444444444
= 13600 +23444444444-23444444444
= 13600 + 0 Since +23444444444-23444444444 = 0
= 13600.
So, the simplified value of the given expression is 13600.
Hope this helps you!.