To solve, isolate the x. Cross multiply
3/13(13)(5) = x/5(5)(13)
3(5) = (13)x
Simplify
13x = 15
Isolate the x. Divide by 13.
13x/13 = 15/13
x = 15/13
x = 1.2
1.2 is your answer
hope this helps
70 ft because 7 is bigger than 5 and 7x10=70
Answer:
19.4in
Step-by-step explanation:
1) formula for area of a triangle:
(b*h)/2=a
the area and height are already given so lets substitute them in the formula.
(b*23.8)/2=230.86
1) multiply by 2 on both sides
b*23.8=461.72
divide by 23.8 on both sides
b=19.4
the base is 19.4 in
hope this helps
Answer:
thank you so much
Step-by-step explanation:
Answer:
Δ JKL is similar to Δ ABC ⇒ D
Step-by-step explanation:
Similar triangles have equal angles in measures
In ΔABC
∵ m∠A = 15°
∵ m∠B = 120
∵ The sum of the measures of the interior angles of a Δ is 180°
∴ m∠A + m∠B + m∠C = 180°
→ Substitute the measures of ∠A and ∠B
∵ 15 + 120 + m∠C = 180
→ Add the like terms in the left side
∴ 135 + m∠C = 180
→ Subtract 135 from both sides
∴ 135 - 135 + m∠C = 180 - 135
∴ m∠C = 45°
The similar Δ to ΔABC must have the same measures of angles
If triangles ABC and JKL are similar, then
m∠A must equal m∠J
m∠B must equal m∠K
m∠C must equal m∠L
∵ m∠J = 15°
∴ m∠A = m∠J
∵ m∠L = 45°
∴ m∠C = m∠L
∵ m∠J + m∠K + m∠L = 180°
→ Substitute the measures of ∠J and ∠L
∵ 15 + m∠K + 45 = 180
→ Add the like terms in the left side
∴ 60 + m∠K = 180
→ Subtract 60 from both sides
∴ 60 - 60 + m∠K = 180 - 60
∴ m∠K = 120°
∴ m∠B = m∠K
∴ Δ JKL is similar to Δ ABC