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Ilia_Sergeevich [38]
3 years ago
6

Jay simplified the expression -3 × (3 + 12 ÷ 3) - 4. For his first step, he added 3 + 12 to get 15. What was Jay’s error?

Mathematics
2 answers:
N76 [4]3 years ago
8 0

Answer:

i dont know

Step-by-step explanation:

ale4655 [162]3 years ago
3 0

Answer:

He should have divided 12 ÷ 3 first.

Step-by-step explanation:

Following PEMDAS/BODMAS, the first step is solving equations in parentheses. Since the parentheses contain a multi-step equation, Jay needs to follow PEMDAS for inside the parentheses as well. Instead of adding 3+12 first, he should have done division first (12  ÷ 3).

How the problem should be solved:

-3 × (3 + 12 ÷ 3) - 4

-3 × (3 + 4) -4

-3 × 7 - 4

-21 - 4

-25

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6 0
3 years ago
Please help!! What is the solution to the quadratic inequality? 6x2≥10+11x
fredd [130]

Answer:

The solution of the inequation 6\cdot x^{2} \geq 10 + 11\cdot x is \left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right).

Step-by-step explanation:

First of all, let simplify and factorize the resulting polynomial:

6\cdot x^{2} \geq 10 + 11\cdot x

6\cdot x^{2}-11\cdot x -10 \geq 0

6\cdot \left(x^{2}-\frac{11}{6}\cdot x -\frac{10}{6} \right)\geq 0

Roots are found by Quadratic Formula:

r_{1,2} = \frac{\left[-\left(-\frac{11}{6}\right)\pm \sqrt{\left(-\frac{11}{6} \right)^{2}-4\cdot (1)\cdot \left(-\frac{10}{6} \right)} \right]}{2\cdot (1)}

r_{1} = \frac{5}{2} and r_{2} = -\frac{2}{3}

Then, the factorized form of the inequation is:

6\cdot \left(x-\frac{5}{2}\right)\cdot \left(x+\frac{2}{3} \right)\geq 0

By Real Algebra, there are two condition that fulfill the inequation:

a) x-\frac{5}{2} \geq 0 \,\wedge\,x+\frac{2}{3}\geq 0

x \geq \frac{5}{2}\,\wedge\,x \geq-\frac{2}{3}

x \geq \frac{5}{2}

b) x-\frac{5}{2} \leq 0 \,\wedge\,x+\frac{2}{3}\leq 0

x \leq \frac{5}{2}\,\wedge\,x\leq-\frac{2}{3}

x\leq -\frac{2}{3}

The solution of the inequation 6\cdot x^{2} \geq 10 + 11\cdot x is \left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right).

3 0
4 years ago
What sequence of transformations map ABC to PQR?
ValentinkaMS [17]

Answer:

The answer is C

Step-by-step explanation:

Because... if you start in point A and do what C say it will bring you to the same point as the second triangle

Hopes this helps❤️

8 0
3 years ago
) For which values of x is f '(x) zero? (Enter your answers as a comma-separated list.) x = (No Response) For which values of x
grigory [225]

Answer:

Check below, please

Step-by-step explanation:

Step-by-step explanation:

1.For which values of x is f '(x) zero? (Enter your answers as a comma-separated list.)

When the derivative of a function is equal to zero, then it occurs when we have either a local minimum or a local maximum point. So for our x-coordinates we can say

 f'(x)=0\: at \:x=2, and\: x=-2

2. For which values of x is f '(x) positive?

Whenever we have  

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then function is increasing. Since if we could start tracing tangent lines over that graph, those tangent lines would point up.

 f'(x)>0 \:at [-4,-2) \:and\:(2, \infty)

3. For which values of x is f '(x) negative?  

On the other hand, every time the function is decreasing its derivative would be negative. The opposite case of the previous explanation. So

 f'(x)

4.What do these values mean?

 f(x) \:is \:increasing\:when\:f'(x) >0\\\\f(x)\:is\:decreasing\:when f'(x)

5.(b) For which values of x is f ''(x) zero?

In its inflection points, i.e. when the concavity of the curve changes. Since the function was not provided. There's no way to be precise, but roughly

at x=-4 and x=4

6 0
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